Assuming the date and time is 09/09/2009 09:09:09, what value will the following statement return SELECT TO_CHAR(TRUNC(SYSDATE),'MM/DD/YYYY HH24:MI:SS') FROM dual;
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Assuming the date and time is 09/09/2009 09:09:09, what value will the following statement return SELECT TO_CHAR(TRUNC(SYSDATE),'MM/DD/YYYY HH24:MI:SS') FROM dual;
09/09/2009 00:00:00
09/09/2009 09:09:09AM
09/09/2009
09/09/2009 09:09:09
None of the above.
The given statement is:
SELECT TO_CHAR(TRUNC(SYSDATE),'MM/DD/YYYY HH24:MI:SS') FROM dual;
Let's break down the statement:
TRUNC(SYSDATE): This truncates the current date and time to the nearest day, setting the time component to 00:00:00.
TO_CHAR(TRUNC(SYSDATE),'MM/DD/YYYY HH24:MI:SS'): This converts the truncated date and time to a string format with the specified format mask.
Considering the given date and time is 09/09/2009 09:09:09, when we truncate this date and time, the time component will be set to 00:00:00, resulting in 09/09/2009 00:00:00.
Therefore, the statement will return "09/09/2009 00:00:00".
The correct answer is A) 09/09/2009 00:00:00.
TRUNC(SYSDATE) strips off the time portion of the current date, effectively setting the time to midnight (00:00:00) while keeping the date unchanged. TO_CHAR then formats that truncated value using the given mask, so the output shows the correct date with all-zero time components, not the actual current time.