Multiple choice technology programming languages

public class Demo { public static void main(String[] args) { String s1="Hello"; String s2="Hello"; if(s1==s2) System.out.println("Hello...."); else System.out.println("Hi...."); } } what is the result?

  1. Hello....

  2. Hi....

  3. Compilation error

  4. Runtime error
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Java uses string literal pooling. When s1 and s2 are both assigned "Hello", they reference the same string literal object in the pool. The == operator compares references, not content. Since both variables point to the same pooled string, s1 == s2 returns true, printing "Hello....". Option B is wrong because the references are equal. Options C and D are incorrect as the code compiles and runs normally.

AI explanation

To answer this question, let's go through each option:

Option A) Hello.... - This option is correct because the condition s1 == s2 is true. In Java, when comparing two strings using the == operator, it checks if the two strings are the same object in memory. In this case, both s1 and s2 are assigned the same string literal "Hello", so they refer to the same object in memory. Therefore, the condition is true, and the code will print "Hello....".

Option B) Hi.... - This option is incorrect because the condition s1 == s2 is true, as explained above. Therefore, the code will not execute the else block and will not print "Hi....".

Option C) Compilation error - This option is incorrect. The code will compile without any errors as there are no syntax errors or violations of Java language rules.

Option D) Runtime error - This option is incorrect. The code will run without any errors as there are no issues that would cause a runtime error.

The correct answer is A) Hello....

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