To answer this question, let's go through each option:
Option A) Hello.... - This option is correct because the condition s1 == s2 is true. In Java, when comparing two strings using the == operator, it checks if the two strings are the same object in memory. In this case, both s1 and s2 are assigned the same string literal "Hello", so they refer to the same object in memory. Therefore, the condition is true, and the code will print "Hello....".
Option B) Hi.... - This option is incorrect because the condition s1 == s2 is true, as explained above. Therefore, the code will not execute the else block and will not print "Hi....".
Option C) Compilation error - This option is incorrect. The code will compile without any errors as there are no syntax errors or violations of Java language rules.
Option D) Runtime error - This option is incorrect. The code will run without any errors as there are no issues that would cause a runtime error.
The correct answer is A) Hello....