Given: class Mineral { } class Gem extends Mineral { } class Miner { static int x = 7; static String s = null; public static void getWeight(Mineral m) { int y = 0 / x; System.out.print(s + " "); } public static void main(String[] args) { Mineral[] ma = {new Mineral(), new Gem()}; for(Object o : ma) getWeight((Mineral) o); } } And the command-line invocation: java Miner.java What is the result?

technology programming languages

  1. null

  2. null null

  3. A ClassCastException is thrown.

  4. A NullPointerException is thrown.

  5. A NoClassDefFoundError is thrown.

  6. An ArrayIndexOutOfBoundsException is thrown.

Show answer
Correct Option: B

AI Explanation

To answer this question, let's go through each option to understand why it is correct or incorrect:

Option A) null - This option is incorrect because the output is not just "null". The output will contain two values.

Option B) null null - This option is correct. The output will be "null null".

Option C) A ClassCastException is thrown. - This option is incorrect. There is no explicit type casting in the given code, so a ClassCastException will not be thrown.

Option D) A NullPointerException is thrown. - This option is incorrect. Although the variable "s" is initialized to null, a NullPointerException will not be thrown because null can be concatenated with a string in Java without causing an exception.

Option E) A NoClassDefFoundError is thrown. - This option is incorrect. There is no indication in the code that a NoClassDefFoundError will be thrown.

Option F) An ArrayIndexOutOfBoundsException is thrown. - This option is incorrect. There is no array index access in the code, so an ArrayIndexOutOfBoundsException will not be thrown.

The correct answer is B. The output will be "null null" because the method getWeight() is called twice, once for each element in the ma array. In each call, the variable s is concatenated with a space and printed. Since s is initialized to null, the output will be "null null".

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