To answer this question, we need to understand the concept of memory management in programming.
When a pointer is deleted twice, it can cause a trap. This means that the program can encounter a runtime error or crash.
Here's an explanation for each option:
Option A) It can abort the program - This option is incorrect because deleting a pointer twice does not necessarily result in program abortion. Instead, it can cause a runtime error or crash.
Option B) It can cause a failure - This option is incorrect because "failure" is a broad term and does not specifically describe the consequence of deleting a pointer twice. The consequence is more accurately described as a runtime error or crash.
Option C) It can cause an error - This option is correct because deleting a pointer twice is considered an error in memory management. It violates the principle of proper memory deallocation and can lead to unexpected behavior.
Option D) It can cause a trap - This option is correct because deleting a pointer twice can cause a trap. A trap refers to a runtime error or crash that occurs when the program attempts to access invalid memory.
The correct answer is D) It can cause a trap. This option accurately describes the consequence of deleting a pointer twice, as it can result in a runtime error or crash.