What happens when a pointer is deleted twice?
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It can abort the program
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It can cause a failure
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It can cause an error
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It can cause a trap
Deleting a pointer twice causes undefined behavior, often manifesting as a CPU trap when the memory manager detects the invalid operation. The program may crash or corrupt memory silently.
To answer this question, we need to understand the concept of memory management in programming.
When a pointer is deleted twice, it can cause a trap. This means that the program can encounter a runtime error or crash.
Here's an explanation for each option:
Option A) It can abort the program - This option is incorrect because deleting a pointer twice does not necessarily result in program abortion. Instead, it can cause a runtime error or crash.
Option B) It can cause a failure - This option is incorrect because "failure" is a broad term and does not specifically describe the consequence of deleting a pointer twice. The consequence is more accurately described as a runtime error or crash.
Option C) It can cause an error - This option is correct because deleting a pointer twice is considered an error in memory management. It violates the principle of proper memory deallocation and can lead to unexpected behavior.
Option D) It can cause a trap - This option is correct because deleting a pointer twice can cause a trap. A trap refers to a runtime error or crash that occurs when the program attempts to access invalid memory.
The correct answer is D) It can cause a trap. This option accurately describes the consequence of deleting a pointer twice, as it can result in a runtime error or crash.