Multiple choice technology databases

When you try to save 34567.2255 into a column defined as NUMBER(7,2) what value is actually saved?

  1. 34567.00

  2. 34567.22

  3. 34567.23

  4. 3456.22
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

When saving 34567.2255 to a NUMBER(7,2) column, the database must fit 5 digits before the decimal and 2 after. Since the value exceeds 2 decimal places, rounding occurs. Standard rounding rules apply: 34567.2255 rounds to 34567.23 because the third decimal digit is 5. The precision (7) accommodates all digits, and the scale (2) forces rounding to two decimal places.

AI explanation

To answer this question, we need to understand how the NUMBER data type works in Oracle.

The NUMBER data type is used to store decimal numbers in Oracle. The format for the NUMBER data type is NUMBER(p, s), where p represents the precision and s represents the scale. The precision (p) is the total number of digits that can be stored in the column, and the scale (s) is the number of digits to the right of the decimal point.

In this case, the column is defined as NUMBER(7,2), which means it can store a total of 7 digits, with 2 digits to the right of the decimal point.

When we try to save the value 34567.2255 into this column, Oracle will round the value according to the specified scale. In this case, it will round the value to 2 decimal places.

So, the value that is actually saved in the column will be 34567.23.

Let's go through each option to understand why it is correct or incorrect:

Option A) 34567.00 - This option is incorrect because it does not take into account the rounding that occurs when saving the value into the column.

Option B) 34567.22 - This option is incorrect because it does not take into account the rounding that occurs when saving the value into the column.

Option C) 34567.23 - This option is correct because it correctly represents the value that is actually saved in the column, after rounding to 2 decimal places.

Option D) 3456.22 - This option is incorrect because it does not represent the value that is actually saved in the column.

The correct answer is C. The value that is actually saved in the column is 34567.23.

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