Multiple choice technology programming languages

What will happen when you attempt to compile and run the following code? int Output = 10; boolean b1 = false; if((b1 == true) && ((Output += 10) == 20)) { System.out.println("We are equal " + Output); } else { System.out.println("Not equal! " + Output); }

  1. Compilation error, attempting to perform binary comparison on logical data type.

  2. Compilation and output of "We are equal 10".

  3. Compilation and output of "Not equal! 20".

  4. Compilation and output of "Not equal! 10".
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D Correct answer
Explanation

The code uses the && operator which short-circuits. Since b1 is false, the right side ((Output += 10) == 20) is never evaluated. Output remains 10, not 20. The condition is false, so the else block executes, printing 'Not equal! 10'. The key is understanding short-circuit evaluation with && - if the left operand is false, the right is skipped.

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