To understand setTimeOut(), the user needs to know how JavaScript functions and the concept of asynchronous programming.

setTimeOut() is a built-in function in JavaScript that allows you to execute a block of code after a specified delay.

Now, let's go through each option and explain why it is right or wrong:

A. The statement(s) it executes run(s) only once. - This option is correct. The block of code passed as the first parameter to setTimeOut() is executed only once after the specified delay. If you want to execute it repeatedly, you can use setInterval().

B. It pauses the script in which it is called. - This option is incorrect. setTimeOut() is an asynchronous function, which means that it does not pause the script. Instead, it schedules the block of code to run after the specified delay and continues executing the rest of the code.

C. clearTimeOut() won't stop its execution. - This option is incorrect. If you want to stop the execution of setTimeOut() before it runs the scheduled block of code, you can use clearTimeout(). This function takes the ID returned by setTimeOut() as a parameter and cancels the execution.

D. The delay is measured in hundredths of a second. - This option is incorrect. The delay is measured in milliseconds, not hundredths of a second. For example, if you want to delay the execution of a block of code for 1 second, you can pass 1000 (1000 milliseconds = 1 second) as the delay parameter to setTimeOut().

Therefore, the correct answer is:

The Answer is: A