Given: class Fizz { int x = 5; public static void main(String[] args) { final Fizz f1 = new Fizz(); Fizz f2 = new Fizz(); Fizz f3 = FizzSwitch(f1,f2); System.out.println((f1 == f3) + " " + (f1.x == f3.x)); } static Fizz FizzSwitch(Fizz x, Fizz y) { final Fizz z = x; z.x = 6; return z; } } What is the result?

  1. true true

  2. false true

  3. true false

  4. false false

  5. Compilation fails.

  6. An exception is thrown at runtime


Correct Option: A
Explanation:

Explanation: Let's go through the code step by step to understand the result.

  1. We have a class called "Fizz" with an instance variable "x" initialized to 5.

  2. In the main method, we create two instances of the "Fizz" class - f1 and f2.

  3. We then call the static method "FizzSwitch" passing f1 and f2 as arguments. In this method, we declare a final variable "z" and assign it the value of "x" (which is f1).

  4. Next, we modify the value of "x" using the "z" reference. Therefore, the value of "x" in f1 is changed to 6.

  5. Finally, we return the reference "z" (which is f1) and assign it to the variable "f3".

  6. In the println statement, we compare if f1 and f3 are the same object reference (f1 == f3) and if their instance variable "x" is the same (f1.x == f3.x).

Now let's analyze the options:

Option A) true true - This option is correct because f1 and f3 refer to the same object, and the value of "x" in both objects is 6.

Option B) false true - This option is incorrect because f1 and f3 refer to the same object, so f1 == f3 should be true.

Option C) true false - This option is incorrect because f1 and f3 refer to the same object, so f1 == f3 should be true.

Option D) false false - This option is incorrect because f1 and f3 refer to the same object, so f1 == f3 should be true.

Option E) Compilation fails - The code does not have any compilation errors, so this option is incorrect.

Option F) An exception is thrown at runtime - The code does not have any exceptional behavior, so this option is incorrect.

The correct answer is option A) true true. This option is correct because f1 and f3 refer to the same object, and the value of "x" in both objects is 6.

Therefore, the result of the code is "true true".

The correct answer is option A.

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