Given: class Mixer { Mixer() { } Mixer(Mixer m) { ml = m;} Mixer m1; public static void main(String[] args) { Mixer m2 = new Mixer(); Mixer m3 = new Mixer(m2); m3.go(); Mixer m4 = m3.m1; m4.go(); Mixer m5 = m2.m1; m5.go(); } void go() { System.out.print("hi "); } } What is the result?

  1. hi

  2. hi hi

  3. hi hi hi

  4. Compilation fails

  5. hi, followed by an exception

  6. hi hi, followed by an exception


Correct Option: F

AI Explanation

To answer this question, let's go through each line of the code:

  1. In the Mixer class, there are two constructors:

    • Mixer() - This is a default constructor that does not take any arguments.
    • Mixer(Mixer m) - This constructor takes a Mixer object as an argument and assigns it to the instance variable ml.
  2. Inside the main method:

    • Mixer m2 = new Mixer(); - This creates a new Mixer object called m2 using the default constructor.
    • Mixer m3 = new Mixer(m2); - This creates a new Mixer object called m3 using the constructor that takes a Mixer object as an argument. The argument m2 is passed to this constructor.
    • m3.go(); - This calls the go() method on m3, which prints "hi ".
    • Mixer m4 = m3.m1; - This assigns the value of m3.m1 (which is null because it has not been initialized) to m4.
    • m4.go(); - This calls the go() method on m4, which also prints "hi ".
    • Mixer m5 = m2.m1; - This assigns the value of m2.m1 (which is null because it has not been initialized) to m5.
    • m5.go(); - This calls the go() method on m5, which also prints "hi ".

The output of the code will be: "hi hi ".

Therefore, the correct answer is F) "hi hi, followed by an exception".

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