Given: class Mixer { Mixer() { } Mixer(Mixer m) { ml = m;} Mixer m1; public static void main(String[] args) { Mixer m2 = new Mixer(); Mixer m3 = new Mixer(m2); m3.go(); Mixer m4 = m3.m1; m4.go(); Mixer m5 = m2.m1; m5.go(); } void go() { System.out.print("hi "); } } What is the result?

To answer this question, let's go through each line of the code:

1. In the Mixer class, there are two constructors:

   • Mixer() - This is a default constructor that does not take any arguments.
   • Mixer(Mixer m) - This constructor takes a Mixer object as an argument and assigns it to the instance variable ml.

2. Inside the main method:

   • Mixer m2 = new Mixer(); - This creates a new Mixer object called m2 using the default constructor.
   • Mixer m3 = new Mixer(m2); - This creates a new Mixer object called m3 using the constructor that takes a Mixer object as an argument. The argument m2 is passed to this constructor.
   • m3.go(); - This calls the go() method on m3, which prints "hi ".
   • Mixer m4 = m3.m1; - This assigns the value of m3.m1 (which is null because it has not been initialized) to m4.
   • m4.go(); - This calls the go() method on m4, which also prints "hi ".
   • Mixer m5 = m2.m1; - This assigns the value of m2.m1 (which is null because it has not been initialized) to m5.
   • m5.go(); - This calls the go() method on m5, which also prints "hi ".

The output of the code will be: "hi hi ".

Therefore, the correct answer is F) "hi hi, followed by an exception".

• Thanks
• Wrong explanation