To determine the result of the given code, let's go through each option:
Option A) furry bray - This option concatenates the name
variable from the Mammal
class, which is "furry", with the result of the makeNoise()
method from the Zebra
class, which is "bray".
Option B) stripes bray - This option concatenates the name
variable from the Zebra
class, which is "stripes", with the result of the makeNoise()
method from the Zebra
class, which is "bray". However, the name
variable in the Mammal
class is not used.
Option C) furry generic noise - This option concatenates the name
variable from the Mammal
class, which is "furry", with the result of the makeNoise()
method from the Mammal
class, which is "generic noise".
Option D) stripes generic noise - This option concatenates the name
variable from the Zebra
class, which is "stripes", with the result of the makeNoise()
method from the Mammal
class, which is "generic noise".
Option E) Compilation fails - There are no compilation errors in the given code, so this option is incorrect.
Option F) An exception is thrown at runtime - There are no exceptions thrown in the given code, so this option is incorrect.
The correct answer is Option A) furry bray. This option is correct because it correctly combines the name
variable from the Mammal
class with the result of the makeNoise()
method from the Zebra
class.