What will happen if you attempt to compile and run the following code? Integer ten=new Integer(10); Long nine=new Long (9); System.out.println(ten + nine); int i=1; System.out.println(i + ten);
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19 followed by 20
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19 followed by 11
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Error: Can't convert java lang Integer
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10 followed by 1
The code attempts to add Integer and Long wrapper objects directly using the + operator. Java does not support automatic unboxing and arithmetic between different wrapper object types - Integer + Long is invalid. You must first convert them to primitive types using intValue() or longValue(). The compiler will error on 'ten + nine' because it cannot resolve the + operator for Integer and Long types. The second operation 'i + ten' would work because int auto-unboxes Integer, but the first error prevents compilation.
To answer this question, let's go through each line of code and understand its behavior:
Integer ten = new Integer(10);- This line creates a new instance of theIntegerclass and assigns the value 10 to it.Long nine = new Long(9);- This line creates a new instance of theLongclass and assigns the value 9 to it.System.out.println(ten + nine);- This line attempts to print the sum oftenandnine. Sincetenis anIntegerandnineis aLong, the Java compiler will try to promotetento aLongbefore performing the addition. However, this operation is not supported, and it will result in an error.int i = 1;- This line declares and initializes an integer variableiwith the value 1.System.out.println(i + ten);- This line attempts to print the sum ofiandten. Sincetenis anIntegerandiis anint, the Java compiler will automatically promoteito anIntegerbefore performing the addition. The sum will be 1 + 10 = 11, and it will be printed as the output.
Therefore, the correct answer is C. Error: Can't convert java lang Integer. The code will fail to compile because the addition of an Integer and a Long is not supported.