To determine the result of the given code, let's go through the code step by step:
- The code initializes an integer variable
x
with the value 4.
- It creates a
StringBuffer
object sb
with the initial value "..fedcba".
- The code deletes the characters at positions 3, 4, and 5 from
sb
.
- After deletion,
sb
becomes "..fba".
- The code inserts the string "az" at position 3 in
sb
.
- After insertion,
sb
becomes "..azfba".
- The code checks if the length of
sb
is greater than 6. Since it is, the code executes the following:
- It assigns
x
the value of the index of the first occurrence of the character "b" in sb
.
- The first occurrence of "b" is at index 6.
- Therefore,
x
is set to 6.
- The code deletes the characters at positions (x-3) and (x-2) from
sb
.
- This translates to deleting characters at positions 3 and 4 from
sb
.
- After deletion,
sb
becomes "..azba".
- Finally, the code prints the value of
sb
, which is "..azba".
Therefore, the result is "..azba".
The correct answer is option C.