Multiple choice technology programming languages

Given the following code: public class OrtegorumFunction { public int computeDiscontinuous(int x) { int r = 1; r += X; if ((x > 4) && (x < 10)) { r += 2 * x; } else (x <= 4) { r += 3 * x; } else { r += 4 * x; } r += 5 * x; return r; } public static void main(String [] args) { OrtegorumFunction o = new OrtegorumFunction(); System.out.println("OF(11) is: " + o.computeDiscontinuous (11)); } } What is the result?

  1. OF(11) is: 45

  2. OF(11) is: 56

  3. OF(11) is: 89

  4. OF(11) is: 111

  5. Compilation fails

  6. An exception is thrown at runtime.
Reveal answer Fill a bubble to check yourself
E Correct answer
Explanation

The code has a syntax error on the line 'else (x <= 4) {'. The 'else' statement cannot have a condition in parentheses - that syntax is for 'else if'. When you want a condition, you must use 'else if' not just 'else'. This causes compilation to fail, making option E correct.

AI explanation

The code uses else (x &lt;= 4) { ... } which is invalid Java syntax — an else clause cannot be followed directly by a condition in parentheses; it must be written as else if (x &lt;= 4). Because this is a syntax error, the program never runs and compilation fails, regardless of what value is passed to the method.

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