What is the value of d that will be printed out. public class Test { public final static void main(String[] args) { double d = - 22.22222; System.out.println(Math.ceil(d)); } }

Math.ceil() returns the smallest double value that is greater than or equal to the argument and is a mathematical integer — i.e., it rounds toward positive infinity. For d = -22.22222, the smallest integer-valued double that is still >= -22.22222 is -22.0 (since -22.0 > -22.22222, while -23.0 would be less than it). So Math.ceil(-22.22222) prints '-22.0'. Option A (-23) confuses ceiling with flooring/truncation-toward-negative-infinity; option C drops the negative sign; option D is simply not a value ceil could produce from this input.

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