Given: class Eggs { int doX(Long x, Long y) { return 1; } int doX(long... x) { return 2; } int doX(Integer x, Integer y) { return 3; } int doX(Number n, Number m) { return 4; } public static void main(String[] args) { new Eggs().go(); } void go () { short s = 7; System.out.print(doX(s,s) + " "); System.out.println(doX(7,7)); } } What is the result?
1 1
2 1
3 1
4 1
2 3
4 3
For doX(s,s) with short arguments, boxing to Short (which inherits from Number) is preferred over varargs, resolving to doX(Number, Number) (returning 4). For doX(7,7) with int arguments, boxing to Integer is more specific than Number, resolving to doX(Integer, Integer) (returning 3). Thus, '4 3' is printed.
To determine the result of the given code, let's go through each option and explain why it is correct or incorrect:
Option A) 1 1 - This option is incorrect. The doX() method is overloaded with different parameter types, but none of the overloads accept a short as an argument.
Option B) 2 1 - This option is incorrect. The doX() method is overloaded with different parameter types, but the doX(long... x) overload is not applicable for the given arguments because a short cannot be automatically promoted to a long.
Option C) 3 1 - This option is incorrect. The doX() method is overloaded with different parameter types, but the doX(Integer x, Integer y) overload is not applicable for the given arguments because a short cannot be automatically boxed to an Integer.
Option D) 4 1 - This option is incorrect. The doX() method is overloaded with different parameter types, but the doX(Number n, Number m) overload is not applicable for the given arguments because a short cannot be automatically boxed to a Number.
Option E) 2 3 - This option is incorrect. The doX() method is overloaded with different parameter types, but the doX(long... x) overload is not applicable for the given arguments because a short cannot be automatically promoted to a long. However, the doX(Integer x, Integer y) overload is applicable and will be chosen.
Option F) 4 3 - This option is correct. The doX() method is overloaded with different parameter types, and both the doX(Number n, Number m) overload and the doX(Integer x, Integer y) overload are applicable for the given arguments. However, the doX(Number n, Number m) overload is more specific because it accepts Number parameters, which are the superclasses of Integer. Therefore, it will be chosen for the call doX(s, s). The call doX(7, 7) will choose the doX(Integer x, Integer y) overload.
The correct answer is option F) 4 3.