Given: class Alien { String invade(short ships) { return "a few"; } String invade(short... ships) { return "many"; } } class Defender { public static void main(String [] args) { System.out.println(new Alien().invade(7)); } } What is the result?
many
a few
Compilation fails.
An exception is thrown at runtim
The literal 7 is of type int. Java does not perform implicit narrowing of integer arguments to match method parameters of type short or short.... Since there is no matching method that accepts int arguments, the compiler cannot resolve the call, resulting in a compilation failure.
To answer this question, let's go through each option to understand why it is correct or incorrect:
Option A) many - This option is incorrect because the invade method in the Alien class has two overloaded versions: one that takes a short parameter and one that takes a variable number of short parameters. In this case, the invade method is called with a single int argument (7), so it does not match any of the available methods.
Option B) a few - This option is incorrect for the same reason as option A. The invade method that takes a single short parameter is not called, so this option is not the result.
Option C) Compilation fails. - This option is correct because there is no matching method in the Alien class for the invade method call with an int argument. The compiler will give an error indicating that the method call is ambiguous because it matches both the method with a short parameter and the method with a variable number of short parameters.
Option D) An exception is thrown at runtime - This option is incorrect because the code fails to compile, so it will not even reach the runtime stage. Therefore, no exception will be thrown at runtime.
The correct answer is C. Compilation fails. This option is correct because the method call does not match any of the available methods in the Alien class.