Given: 1. class Dog { } 2. class Beagle extends Dog { } 3. 4. class Kennel { 5. public static void main(String [] arfs) { 6. Beagle bl = new Beagle(); 7. Dog dogl = new Dog(); 8. Dog dog2 = bl; 9. // insert code here 10. } } Which, inserted at line 9, will compile? (Choose all that apply.)

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  1. Beagle b2 = (Beagle) dog1;

  2. Beagle b3 = (Beagle) dog2;

  3. Beagle b4 = dog2;

  4. None of the above statements will compile.

Show answer
Correct Option: A,B

AI Explanation

To answer this question, let's go through each option to understand why it is correct or incorrect:

Option A) Beagle b2 = (Beagle) dog1; - This option will not compile because there is no variable named dog1. The correct variable name is dogl. Additionally, since dogl is of type Dog and not Beagle, it cannot be cast to Beagle.

Option B) Beagle b3 = (Beagle) dog2; - This option will compile. Since dog2 is of type Dog, which is a superclass of Beagle, it can be cast to Beagle.

Option C) Beagle b4 = dog2; - This option will not compile because dog2 is of type Dog and cannot be assigned to a variable of type Beagle without casting.

Option D) None of the above statements will compile. - This option is incorrect because option B (Beagle b3 = (Beagle) dog2;) will compile.

The correct answer is A, B.

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