void main() { int i = 10; long *p=&i; p++; printf("%d",abs(&i-p)); }
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Keep practicing — related questions
- void main() { int i = 10; int *p=&i; p++; printf("%d",(p-&i)); }
- main() { int *p1, i=25; void *p2; p1=&i; p2=&i; p1=p2; p2=p1; printf(“%d”,i); }
- main() { char *p; int *q; long *r; p=q=r=0; p++; q++; r++; printf("%p\t%p\t%p",p,q,r); }
- void main(){ print(“%d”,printf(“What this prints”)) };
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- 1)void main() { int const *p = 5; printf(“%d”,++(*p)); }
- main(){ int x=5; printf("%d %d %d\n", x,x<<2,x=x>>2); }