void main() { int ; _=100; printf("%d",); }
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Keep practicing — related questions
- void main() { int a= 100; void *j= &a; int *k= j; printf("%u", *k); }
- void main() { int x; x=1; x= 2 + 2 * x++; printf("%d", x); }
- void main() { int i = 10; int *p=&i; p++; printf("%d",(p-&i)); }
- 3) void main() { int x=10; (x<0) ? (int a = 100) : (int a=1000); printf(“%d”,a); }
- main() { extern i; printf("%d",i); { int i=20; printf("%d",i); } }
- void main(){ print(“%d”,printf(“What this prints”)) };
- void main(){ print(“%d”,printf(“What this prints”)) };
- The following program main() {*int i=100; int M(); printf(“%d“,(*M)(i));} int M(x)int x{printf(“%d”,++x);}