int i=5; if(i=4) { printf("A"); } else { printf("B"); }
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Keep practicing — related questions
- void main() { int i; for (i=5; ++i; i-=3) printf("%d ",i); }
- void main() { int a=5,b=4,c=10; *((a>b) ? &a : &b) = (a+b>c); printf(%d %d,a,b); }
- What is the output of the following code fragment? int i = 10; if(i = printf(“%d”, i)) { printf(“%d ”, i); }
- main(){ int x=5; printf("%d %d %d\n", x,x<<2,x=x>>2); }
- What is the output?int i = 3;if (!i) i++; i++;if (i==3) i+=2; i+=2;printf("%d\n", i);
- What gets printed? int i = 3; if (!i) i++; i++; if (i==3) i+=2; i+=2; printf("%d\n", i);
- int i=3, j=4; if( i==3 || j++ ) { printf("%d\n",j); } This will print: 5
- Find the output of this program. main() { int i=5; printf(“%d”,i=++i ==6); }