abc(){ _AX = 1000;} main(){ int i; i = abc(); printf("%d",i); }
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1000
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garbage value
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undefined symbol _AX
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none of these
The function sets the register variable _AX to 1000. In many C compilers (especially older ones like Turbo C), return values are passed through the _AX register. When abc() is called, it sets _AX=1000, and main retrieves this as the return value i.
To understand the correct answer, let's analyze the code step by step:
- The code defines a function named
abc()which takes no arguments. - Inside the
abc()function, the value of the_AXvariable is set to 1000. - The
main()function is defined. - Inside the
main()function, an integer variableiis declared. - The
ivariable is assigned the return value of theabc()function. - The
printf()function is used to print the value ofiusing the format specifier%d.
Now, let's go through the options to determine the correct answer:
A) 1000 - This option is correct. The abc() function sets the value of _AX to 1000, and this value is assigned to the variable i in the main() function. Therefore, when the printf() function is called, it prints the value of i, which is 1000.
B) garbage value - This option is incorrect. The value assigned to i is not a garbage value. It is a valid value that was explicitly set in the abc() function.
C) undefined symbol _AX - This option is incorrect. The _AX symbol is defined in the code, and its value is set to 1000 in the abc() function. Therefore, it is not an undefined symbol.
D) none of these - This option is incorrect. As explained above, option A is the correct answer.
Therefore, the correct answer is A) 1000.