abc(){ _AX = 1000;} main(){ int i; i = abc(); printf("%d",i); }

  1. 1000

  2. garbage value

  3. undefined symbol _AX

  4. none of these


Correct Option: A

AI Explanation

To understand the correct answer, let's analyze the code step by step:

  1. The code defines a function named abc() which takes no arguments.
  2. Inside the abc() function, the value of the _AX variable is set to 1000.
  3. The main() function is defined.
  4. Inside the main() function, an integer variable i is declared.
  5. The i variable is assigned the return value of the abc() function.
  6. The printf() function is used to print the value of i using the format specifier %d.

Now, let's go through the options to determine the correct answer:

A) 1000 - This option is correct. The abc() function sets the value of _AX to 1000, and this value is assigned to the variable i in the main() function. Therefore, when the printf() function is called, it prints the value of i, which is 1000.

B) garbage value - This option is incorrect. The value assigned to i is not a garbage value. It is a valid value that was explicitly set in the abc() function.

C) undefined symbol _AX - This option is incorrect. The _AX symbol is defined in the code, and its value is set to 1000 in the abc() function. Therefore, it is not an undefined symbol.

D) none of these - This option is incorrect. As explained above, option A is the correct answer.

Therefore, the correct answer is A) 1000.

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