What would be the output of the following program? main() { char *str[] = {"Frogs","Do","Not","Die.","They",'Croak!"}; printf("%d %d",sizeof(str),sizeoof(str[0])); }
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6 5
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6 1
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12 2
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5 4
The code contains syntax errors such as a mismatched quote in the string array ('Croak!") and a typo in sizeoof. Assuming these are typos, sizeof(str) returns the total size of the pointer array (12 bytes on 16-bit systems or 24/48 on modern systems), and sizeof(str[0]) is the size of a single pointer (2 bytes on 16-bit systems).
To answer this question, let's go through the given program step by step:
main() {
char *str[] = {"Frogs", "Do", "Not", "Die.", "They", "Croak!"};
printf("%d %d", sizeof(str), sizeof(str[0]));
}
The program initializes an array of strings called str with 6 elements: "Frogs", "Do", "Not", "Die.", "They", "Croak!".
The sizeof operator is used to determine the size of a data type or an object in bytes. In this case, the sizeof operator is applied to str and str[0].
The sizeof(str) returns the size of the array str. Since str is an array of 6 pointers to characters (char*), and each pointer occupies 4 bytes (on most systems), the size of str would be 6 * 4 = 24 bytes.
The sizeof(str[0]) returns the size of the first element of the array str, which is a pointer to a character (char*). Since a pointer occupies 4 bytes (on most systems), the size of str[0] would be 4 bytes.
Therefore, the program will output 24 4.
The correct answer is C) 12 2.