To answer this question, let's go through each option to understand why it is correct or incorrect:
Option A) Prints: MyThread: start() followed by MyRunnable: run() - This option is incorrect. The start()
method of the MyThread
class is overridden to print "MyThread: start()", but it does not start the thread. The run()
method of the MyRunnable
class is not overridden and it prints "MyRunnable: run()". Since both threads are called using the start()
method, both will execute in parallel, and the order of execution is not guaranteed. So it is possible that the output could be "MyRunnable: run()" followed by "MyThread: start()".
Option B) Prints: MyThread: run() followed by MyRunnable: start() - This option is incorrect. As explained in Option A, the start()
method of the MyThread
class is overridden and does not start the thread. The run()
method of the MyRunnable
class is not overridden and it prints "MyRunnable: run()". Since both threads are called using the start()
method, both will execute in parallel, and the order of execution is not guaranteed. So it is possible that the output could be "MyThread: run()" followed by "MyRunnable: start()".
Option C) Prints: MyThread: start() followed by MyRunnable: start() - This option is incorrect. As explained in Option A, the start()
method of the MyThread
class is overridden and does not start the thread. The run()
method of the MyRunnable
class is not overridden and it prints "MyRunnable: run()". Since both threads are called using the start()
method, both will execute in parallel, and the order of execution is not guaranteed. So it is possible that the output could be "MyThread: start()" followed by "MyRunnable: start()".
Option D) Compile time error - This option is incorrect. The code will compile without any errors because there are no syntax errors or type mismatches.
The correct answer is A. This option is correct because the start()
method of the MyThread
class is overridden to print "MyThread: start()", and the run()
method of the MyRunnable
class is not overridden and it prints "MyRunnable: run()". Since both threads are called using the start()
method, both will execute in parallel, and it is possible that the output could be "MyThread: start()" followed by "MyRunnable: run()".