What results from attempting to compile and run the following code? public class Ternary { public static void main(String args[]) { int a = 5; System.out.println("Value is - " + ((a < 5) ? 9.9 : 9)); } }
prints: Value is - 9
prints: Value is - 5
Compilation error
None of these
The ternary operator expression ((a < 5) ? 9.9 : 9) involves type promotion. Since the second operand (9.9) is a double, the third operand (9) is promoted to double, and the result is 9.0 (not 9). The output is 'Value is - 9.0', which doesn't match option A (9), B (5), or C (compilation error). Therefore D (None of these) is correct. This tests understanding of numeric promotion in ternary expressions.
To answer this question, let's go through each option to understand why it is correct or incorrect:
Option A) prints: Value is - 9 - This option is incorrect. The code snippet will not print "Value is - 9" because the condition a < 5 evaluates to false.
Option B) prints: Value is - 5 - This option is incorrect. The code snippet will not print "Value is - 5" because the condition a < 5 evaluates to false.
Option C) Compilation error - This option is incorrect. The code snippet does not contain any syntax errors and will compile successfully.
Option D) None of these - This option is correct. The code snippet will print "Value is - 9" because the condition a < 5 evaluates to false, and the value 9 is returned as the result of the ternary operator. The result is then concatenated with the string "Value is - " and printed to the console.
The correct answer is D. None of these.