What is the no. of bytes occupied for a variable if it’s defined as PIC S9(7) COMP-3 and PIC S9(10) COMP

  1. 2 and 3

  2. 4 and 5

  3. 7 and 6

  4. none of the above


Correct Option: D

AI Explanation

To determine the number of bytes occupied for a variable in COBOL, you need to consider the data type and the storage format.

In COBOL, the PIC clause is used to define the data type and format of a variable. The S9 format is used for signed numeric variables, and the COMP-3 format is used for packed decimal variables.

For the given variable definitions:

  1. PIC S9(7) COMP-3:

    • The S9(7) indicates a signed numeric variable with a maximum of 7 digits.
    • The COMP-3 format represents packed decimal, which stores each digit using half a byte (nibble).
    • For a packed decimal variable, each digit requires 4 bits (half a byte) of storage.
    • The number of digits in the variable (7) multiplied by the storage required per digit (4 bits) gives us the total storage required.
    • Therefore, the total storage required for this variable is 7 * 4 bits = 28 bits, which is equivalent to 4 bytes.
  2. PIC S9(10) COMP:

    • The S9(10) indicates a signed numeric variable with a maximum of 10 digits.
    • The COMP format represents binary storage, which uses full bytes to store the data.
    • For a binary variable, each byte can store 8 bits.
    • The number of digits in the variable (10) multiplied by the storage required per digit (1 byte) gives us the total storage required.
    • Therefore, the total storage required for this variable is 10 * 1 byte = 10 bytes.

Based on the above explanations, the correct answer is D) none of the above, as the given options do not match the correct number of bytes occupied for the variables.

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