Multiple choice technology programming languages

Given: 11. public static void main(String[] args) { 12. String str = “null’; 13. if (str == null) { 14. System.out.println(”null”); 15. } else (str.length() == 0) { 16. System.out.println(”zero”); 17. } else { 18. System.out.println(”some”); 19. } 20. } ‘What is the result?

  1. null

  2. zero

  3. some

  4. Compilation fails.

  5. An exception is thrown at runtime.
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

The code fails to compile because of a syntax error in the 'else' block. In Java, an 'else' statement cannot have a condition. It should be 'else if (str.length() == 0)'. Additionally, the string literal uses a mismatched quote ('null’).

AI explanation

To answer this question, let's go through each option and analyze the code:

Option A) null - This option is incorrect because the code does not print "null" in this scenario.

Option B) zero - This option is incorrect because the code does not print "zero" in this scenario.

Option C) some - This option is incorrect because the code does not print "some" in this scenario.

Option D) Compilation fails - This option is correct. The code will fail to compile due to a syntax error on line 13. The line String str = "null'; has a syntax error because the closing double quote is missing. It should be String str = "null";.

Option E) An exception is thrown at runtime - This option is incorrect because the code does not throw an exception at runtime. The code fails to compile before it can be executed.

Therefore, the correct answer is D) Compilation fails.

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