8 What will happen if you attempt to compile and run the following code? Integer ten=new Integer(10); Long nine=new Long (9); System.out.println(ten + nine); int i=1; System.out.println(i + ten);

To answer this question, let's analyze each line of code and the corresponding output.

1. Integer ten = new Integer(10);

   • This line creates an Integer object named ten with a value of 10.

2. Long nine = new Long(9);

   • This line creates a Long object named nine with a value of 9.

3. System.out.println(ten + nine);

   • In this line, the + operator is used to concatenate ten and nine.
   • When using the + operator with objects, the toString() method is called on each object, and the resulting strings are concatenated.
   • The toString() method for Integer and Long classes converts the objects to their corresponding string representations.
   • Therefore, the output of this line will be "19" (10 + 9).

4. int i = 1;

   • This line creates an int variable named i with a value of 1.

5. System.out.println(i + ten);

   • In this line, the + operator is used to add i and ten.
   • Since ten is an Integer object, it will be unboxed to its corresponding int value before the addition.
   • Therefore, the expression will be evaluated as 1 + 10, resulting in the output "11".

Based on the above analysis, the correct answer is:

A. 19 followed by 20

• Thanks
• Wrong explanation