8 What will happen if you attempt to compile and run the following code? Integer ten=new Integer(10); Long nine=new Long (9); System.out.println(ten + nine); int i=1; System.out.println(i + ten);

  1. a. 19 followed by 20

  2. b. 19 followed by 11

  3. c. Compile time error

  4. d. 10 followed by 1


Correct Option: A

AI Explanation

To answer this question, let's analyze each line of code and the corresponding output.

  1. Integer ten = new Integer(10);

    • This line creates an Integer object named ten with a value of 10.
  2. Long nine = new Long(9);

    • This line creates a Long object named nine with a value of 9.
  3. System.out.println(ten + nine);

    • In this line, the + operator is used to concatenate ten and nine.
    • When using the + operator with objects, the toString() method is called on each object, and the resulting strings are concatenated.
    • The toString() method for Integer and Long classes converts the objects to their corresponding string representations.
    • Therefore, the output of this line will be "19" (10 + 9).
  4. int i = 1;

    • This line creates an int variable named i with a value of 1.
  5. System.out.println(i + ten);

    • In this line, the + operator is used to add i and ten.
    • Since ten is an Integer object, it will be unboxed to its corresponding int value before the addition.
    • Therefore, the expression will be evaluated as 1 + 10, resulting in the output "11".

Based on the above analysis, the correct answer is:

A. 19 followed by 20

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