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You have declared a single dimensional array of type int using the following code: int [] MyInt = new int [10]; You are attempting to initialize all of the arrays segments with a for loop using the following code: for (int x = 0; x <= 10; x++) { MyInt[x] = x; } What will happen when you attempt to compile the program that contains this code?

    1. The program will run successfully with no errors or warnings.
    1. The program will halt with a runtime exception.
    1. The program will halt with a compiler error.
    1. The program will run successfully with no errors but a warning will be generated.
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B Correct answer
Explanation

The array has indices 0-9, but the loop condition x <= 10 includes x=10. Attempting MyInt[10] throws ArrayIndexOutOfBoundsException at runtime. The loop should use x < 10.

AI explanation

The array MyInt has 10 valid indices, 0 through 9, but the loop condition x &lt;= 10 lets x reach 10, which is one past the last valid index. This compiles fine — array bounds aren't checked by the compiler — but at runtime, when x equals 10, the JVM throws an ArrayIndexOutOfBoundsException, halting the program.

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