Assuming that the serializeBanana() and the deserializeBanana() methods will correctly use Java serialization and given: 13. import java.io.*; 14. class Food implements Serializable {int good = 3;} 15. class Fruit extends Food {int juice = 5;} 16. public class Banana extends Fruit { 17. int yellow = 4; 18. public static void main(String [] args) { 19. Banana b = new Banana(); Banana b2 = new Banana(); 20. b.serializeBanana(b); // assume correct serialization 21. b2 = b.deserializeBanana(); // assume correct 22. System.out.println("restore "+b2.yellow+ b2.juice+b2.good); 24. } 25. // more Banana methods go here 50. } What is the result?

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  1. restore 400

  2. restore 403

  3. restore 453

  4. Compilation fails.

  5. An exception is thrown at runtime

Show answer
Correct Option: C

AI Explanation

To answer this question, we need to understand how Java serialization works and how inheritance is handled during serialization.

In Java, serialization is the process of converting an object into a stream of bytes so that it can be stored in memory, a file, or sent over the network. Deserialization is the reverse process, where the byte stream is used to recreate the object.

In this scenario, the classes Food, Fruit, and Banana are all marked as Serializable, which means they can be serialized and deserialized.

Let's go through each option to determine the correct result:

Option A) restore 400 - This option is incorrect because it only considers the value of the yellow variable from Banana. It does not take into account the values of the inherited variables juice and good from Fruit and Food respectively.

Option B) restore 403 - This option is incorrect because it only considers the value of the yellow variable from Banana and the good variable from Food. It does not take into account the value of the inherited variable juice from Fruit.

Option C) restore 453 - This option is correct because it considers the value of all three variables: yellow from Banana, juice from Fruit, and good from Food. When b2 is deserialized, it will have the values yellow = 4, juice = 5, and good = 3, resulting in the output "restore 453".

Option D) Compilation fails - This option is incorrect because the code does not contain any compilation errors.

Option E) An exception is thrown at runtime - This option is incorrect because the question states that the serializeBanana() and deserializeBanana() methods will correctly use Java serialization. Therefore, there will not be any exceptions thrown at runtime.

The correct answer is C) restore 453. This option is correct because it considers the values of all three variables: yellow, juice, and good.

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