To answer this question, let's go through the code:

public class myprog {
    public static void main(String argv[]) {
        System.out.println(argv[2]);
    }
}

The main method is the entry point of the program. It takes a String array called argv as a parameter, which represents the command-line arguments passed to the program.

In the given command line: java myprog good morning, the arguments passed are "myprog", "good", and "morning".

The line System.out.println(argv[2]); attempts to print the element at index 2 of the argv array. In Java, arrays are zero-indexed, which means the first element is at index 0, the second element is at index 1, and so on.

However, in this case, the argv array only has 3 elements: "myprog", "good", and "morning". Since there is no element at index 2, an ArrayIndexOutOfBoundsException will be raised.

Therefore, the correct answer is:

D. Exception raised: "java.lang.ArrayIndexOutOfBoundsException: 2"

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