What will be the output of "echo this || echo that && echo other"?
-
this
-
that
-
this that
-
this other
The || operator runs the next command only if the previous one fails. Since echo this always succeeds (returns exit code 0), the || echo that part is skipped. The && operator then runs echo other because the first part succeeded. Output is "this other".
To answer this question, we need to understand the concept of logical operators in shell scripting.
In shell scripting, the || operator is the logical OR operator, and the && operator is the logical AND operator.
When the || operator is used, the command following it will only be executed if the preceding command fails or returns a non-zero exit status. On the other hand, when the && operator is used, the command following it will only be executed if the preceding command succeeds or returns a zero exit status.
Let's go through the given command step by step:
echo this- This command will be executed and will output "this" to the console.echo that- This command will not be executed because the preceding command (echo this) succeeds and returns a zero exit status.echo other- This command will be executed and will output "other" to the console.
Therefore, the output of the given command "echo this || echo that && echo other" will be "this other".
The correct answer is option D) this other.