What is the output of the following piece of code?
int x = 3, y = 5, z;
z = x + ++y;
printf(“%d”,z);
-
8
-
9
-
10
-
11
The expression 'z = x + ++y' uses a prefix increment on y. First, y is incremented from 5 to 6. Then, the new value of y (6) is added to x (3), resulting in 9. Finally, 9 is assigned to z and printed.
To determine the output of the given code, let's go through each line of code step by step:
int x = 3, y = 5, z;- Here, three variablesx,y, andzare declared and assigned the initial values of 3, 5, and garbage value respectively.z = x + ++y;- In this line, the value ofyis incremented by 1 (++y) and then added to the value ofx. So,ybecomes 6 andx + yis 3 + 6 = 9. The result is stored in the variablez.printf("%d", z);- This line prints the value ofzusing the%dformat specifier, which represents an integer.
Therefore, the output of the code will be 9.
Now, let's go through the options to determine the correct answer:
Option A) 8 - This option is incorrect because the output of the code is 9, not 8.
Option B) 9 - This option is correct. The output of the code is indeed 9.
Option C) 10 - This option is incorrect because the output of the code is not 10.
Option D) 11 - This option is incorrect because the output of the code is not 11.
Therefore, the correct answer is B) 9.