find the odd man out 16, 25, 36, 72, 144, 196, 225
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36
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72
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196
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225
All numbers except 72 are perfect squares: 16=4^2, 25=5^2, 36=6^2, 144=12^2, 196=14^2, 225=15^2. The number 72 cannot be expressed as the square of an integer.
To find the odd one out in the given sequence 16, 25, 36, 72, 144, 196, 225, we need to look for a pattern or rule that applies to most of the numbers in the sequence but not to the odd one out.
Let's analyze the given sequence:
16: 4^2 25: 5^2 36: 6^2 72: 8^2 + 8 (odd one out) 144: 12^2 196: 14^2 225: 15^2
As we can see, most of the numbers in the sequence are perfect squares, except for 72. Therefore, the odd one out in the given sequence is 72 (option B) because it does not follow the pattern of being a perfect square.
Hence, the correct answer is B.