Find the odd man out:- 1,5,14,30,42,55,91
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91
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42
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30
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55
The series represents the sum of squares of consecutive integers: 1^2=1, 1^2+2^2=5, 1^2+2^2+3^2=14, 1^2+2^2+3^2+4^2=30, 1^2+2^2+3^2+4^2+5^2=55. The number 42 does not fit this sequence, as the sum of the first four squares is 30 and the first five is 55.
To find the odd man out in the given sequence 1, 5, 14, 30, 42, 55, 91, we need to analyze the pattern or relationship between the numbers.
Let's examine the differences between consecutive terms:
5 - 1 = 4 14 - 5 = 9 30 - 14 = 16 42 - 30 = 12 55 - 42 = 13 91 - 55 = 36
Looking at the differences, we can observe that they are not following a consistent pattern. However, the difference between 42 and 30 is 12, which is different from the other differences. This suggests that 42 is the odd man out.
Therefore, the correct answer is B) 42.