To solve this question, let's break down the given information:
- When a 5-digit number (ABCDE) is multiplied by 9, the obtained value is a 6-digit number (PQRSTU).
- The sum of the values of the digits in the places of A, C, and D is given as P + R + S = 5.
- The sum of the values of the digits in the places of Q, T, and U is less than 9.
We need to find the value of Q + T + U.
Let's consider the possible values of P, R, and S that satisfy the condition P + R + S = 5:
- P = 1, R = 2, S = 2
- P = 2, R = 1, S = 2
- P = 2, R = 2, S = 1
Now, let's calculate the value of Q + T + U for each case:
P = 1, R = 2, S = 2:
In this case, the value of Q + T + U would be 9 - (1 + 2 + 2) = 4.
P = 2, R = 1, S = 2:
In this case, the value of Q + T + U would be 9 - (2 + 1 + 2) = 4.
P = 2, R = 2, S = 1:
In this case, the value of Q + T + U would be 9 - (2 + 2 + 1) = 4.
Therefore, regardless of the values of P, R, and S, the value of Q + T + U is always 4.
The correct answer is option D) 4.