Tag: java
Questions Related to java
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java.util.HashSet
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java.util.LinkedHashSet
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java.util.List
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java.util.ArrayList
You need to store elements in a collection that guarantees that no duplicates are stored and all elements can be accessed in natural order. Which interface provides that capability?
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java.util.Map
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java.util.Set
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java.util.List
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java.util.Collection
AI Explanation
To answer this question, you need to understand the different interfaces provided by Java's java.util
package for storing collections of elements.
Option A) java.util.Map
- This option is incorrect because a Map
does not guarantee that no duplicates are stored. It allows for key-value pairs, where each key must be unique, but the values can be duplicated.
Option B) java.util.Set
- This option is correct because a Set
interface provides the capability of storing elements in a collection without allowing duplicates. It ensures that every element in the set is unique. Elements in a set are not stored in any particular order, but they can be accessed in a natural order.
Option C) java.util.List
- This option is incorrect because a List
interface allows duplicate elements to be stored. It maintains the insertion order of elements, which means elements can be accessed in the order they were added.
Option D) java.util.Collection
- This option is incorrect because Collection
is not a specific interface that provides the capability mentioned in the question. It is a more general interface that provides basic operations for collections, but it does not guarantee uniqueness or ordering.
The correct answer is B) java.util.Set
. This option is correct because a Set
interface guarantees that no duplicates are stored and allows for accessing elements in a natural order.
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Java.util.Map
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Java.util.List
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Java.util.HashTable
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Java.util.Collection
Hash table based implementation of the Map interface.
Which interface provides the capability to store objects using a key-value pair?
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Java.util.Map
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Java.util.Set
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Java.util.List
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Java.util.Collection
An object that maps keys to values. A map cannot contain duplicate keys; each key can map to at most one value.
Which collection class allows you to associate its elements with key values, and allows you to retrieve objects in FIFO (first-in, first-out) sequence?
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java.util.ArrayList
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java.util.LinkedHashMap
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java.util.HashMap
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java.util.TreeMap
Which collection class allows you to access its elements by associating a key with an element's value, and provides synchronization?
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java.util.SortedMap
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java.util.TreeMap
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java.util.TreeSet
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java.util.Hashtable
To solve this question, the user needs to have a basic understanding of Java collections and their functionalities. Specifically, they need to be familiar with the concept of accessing elements by associating a key with a value and the concept of synchronization in Java collections.
Now, let's go through each option and explain why it is right or wrong:
A. java.util.SortedMap: This option is incorrect. While a SortedMap allows you to access its elements by associating a key with an element's value, it does not provide synchronization. To ensure thread-safe access to a SortedMap, you would need to use additional synchronization mechanisms such as the Collections.synchronizedSortedMap() method.
B. java.util.TreeMap: This option is incorrect. Although a TreeMap allows you to access its elements by associating a key with an element's value, it does not inherently provide synchronization. To achieve synchronized access to a TreeMap, you would need to use additional synchronization mechanisms such as the Collections.synchronizedSortedMap() method.
C. java.util.TreeSet: This option is incorrect. A TreeSet is not a collection class that allows you to access elements by associating a key with an element's value. It is an implementation of the Set interface that stores elements in a sorted and unique order.
D. java.util.Hashtable: This option is correct. Hashtable is a collection class in Java that allows you to access its elements by associating a key with an element's value. It also provides synchronization, meaning that multiple threads can safely access and modify the Hashtable concurrently without causing data inconsistency or other concurrency issues.
Therefore, the correct answer is:
The Answer is: D. java.util.Hashtable
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float f = 1F;
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float f = 1.0;
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float f = "1";
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float f = 1.0d;
What is the numerical range of char?
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0 to 32767
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0 to 65535
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-256 to 255
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-32768 to 32767
AI Explanation
To answer this question, we need to understand the numerical range of the char
data type.
In Java, the char
data type represents a single character and is stored as a 16-bit unsigned integer. The numerical range of char
is from 0 to 65535.
Let's go through each option to understand why it is correct or incorrect:
Option A) 0 to 32767 - This option is incorrect because it does not cover the full range of char
values.
Option B) 0 to 65535 - This option is correct because it represents the full numerical range of the char
data type.
Option C) -256 to 255 - This option is incorrect because it does not cover the positive range of char
values.
Option D) -32768 to 32767 - This option is incorrect because it includes negative values, while char
is an unsigned data type.
The correct answer is Option B. This option is correct because it represents the full numerical range of the char
data type, which is from 0 to 65535.
Which is true about an anonymous inner class?
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It can extend exactly one class and implement exactly one interface.
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It can extend exactly one class and can implement multiple interfaces.
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It can extend exactly one class or implement exactly one interface.
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It can implement multiple interfaces regardless of whether it also extends a class.
To answer this question, one needs to understand the concept of an anonymous inner class in Java.
An anonymous inner class is a class that is defined and instantiated at the same time, without explicitly giving it a name. It is typically used when you need to create a class that is used only once and does not need to be reused.
Now let's go through each option and explain why it is right or wrong:
A. It can extend exactly one class and implement exactly one interface. This option is incorrect. An anonymous inner class can extend a class or implement an interface, but it cannot do both at the same time. It can either extend a class or implement an interface, but not both simultaneously.
B. It can extend exactly one class and can implement multiple interfaces. This option is incorrect. As mentioned earlier, an anonymous inner class cannot extend a class and implement multiple interfaces at the same time. It can either extend a class or implement an interface, but not both simultaneously.
C. It can extend exactly one class or implement exactly one interface. This option is correct. An anonymous inner class can either extend a class or implement an interface. It cannot do both at the same time, but it can choose to extend a class or implement an interface based on the requirements.
D. It can implement multiple interfaces regardless of whether it also extends a class. This option is incorrect. An anonymous inner class can implement multiple interfaces, but only if it does not extend a class. If it extends a class, it can only implement one interface.
Therefore, the correct answer is:
The Answer is: C
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It must be marked final.
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It can be marked abstract.
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It can be marked public.
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It can be marked static.