Which of the following reactions does not take place during leaching for concentration of bauxite?
- $Al _2O _3+2NaOH+3H _2O\rightarrow 2Na[Al(OH) _4]$
- $2Na[Al(OH) _4]+CO _2\rightarrow Al _2O _3.xH _2O+2NaHCO _3$
- $Al _2O _3.2H _2O\xrightarrow{{\Delta}}Al _2O _3+2H _2O$
- $Al _2O _3.xH _2O\xrightarrow{{\Delta}}Al _2O _3+xH _2O$
Reveal answer
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C
Correct answer
Explanation
- Bauxite is the principal ore of aluminium. The impurities present in bauxite are $SiO _2$, iron oxides and titanium oxide ($TiO _2$).
- Concentration is carried out by heating the powdered ore with a concentrated solution of NaOH at 473 – 523 K and 35 – 36 bar pressure. This process is called digestion.
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$Al _2O _3$ is extracted out as sodium aluminate. The impurity, $SiO _2$ too dissolves forming sodium silicate. Other impurities are left behind.
$Al _2O _3+2NaOH+3H _2O \rightarrow 2Na[Al(OH) _4]$
- The sodium aluminate present in solution is neutralised by passing $CO _2$ gas and hydrated $Al _2O _3$ is precipitated. At this stage, small amount of freshly prepared sample of hydrated$Al _2O _3$ is added to the solution. This is called seeding. It induces the precipitation.
$2Na[Al(OH) _4]+CO _2 \rightarrow Al _2O _3.xH _2O+2NaHCO _3$
- Sodium silicate remains in the solution and hydrated alumina is filtered, dried and heated to give back pure$Al _2O _3$.
$Al _2O _3.xH _2O \rightarrow Al _2O _3 + xH _2O$
- Hence, option C is correct answer.