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Multiple choice imperfections in solids solid state the solid state chemistry

Statement-I:  Solids having more $F-$centres possess intense colours.

Statement-II:  Excess of $Na^{+}$ in $NaCl$ solid having F-centres makes it appear to pink.

  1. Statement-I is correct but Statement-II is wrong

  2. Statement-I is wrong but Statement-II is correct

  3. Both Statement-I and Statement-II are correct and Statement-II is correct explanation of Statement-I

  4. Both Statement-I and Statement-II are correct but Statement-II is not correct explanation of Statement-I
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

F-centres are indeed responsible for the intense colors in alkali halides due to the excitation of trapped electrons. However, the color of NaCl with F-centres is yellow, not pink, making statement II incorrect.

Multiple choice imperfections in solids solid state the solid state chemistry

Which of the following statements are correct?

  1. Dislocation of ion from lattice site to interstitial site is called Frenkel defect.

  2. Missing of +ve and -ve ions from their respective position producing a pair of holes is called Schottky defect.

  3. The presence of ions in the vacant interstital sites along with lattice point is called interstital defect.
  4. Non-stoichiometric $NaCl$ is yellow solid.
Reveal answer Fill a bubble to check yourself
A,B,C,D Correct answer
Explanation

Frenkel defect: This type of defect is created when an ion leaves its appropriate site in the lattice and occupies an interstitial site. A hole or vacancy is thus produced in the lattice.

Schottky defect: This type of defect is produced when one cation and anion are missing from their respective positions leaving behind a pair of holes.

The presence of ions in the vacant interstital sites along with lattice point is called interstital defect.

 When alkali metal halides are heated in an atmosphere of vapours of the alkali metal, anion vacancies are created. 


The anions (halide ions) diffuse to the surface of the crystal from their appropriate lattice sites to combine with the newly generated metal cations. The electron lost by the metal atom diffuse through the crystal is known as F-centres. 


The main consequence of metal excess defect in the development of colour in the crystal. For example, when $NaCl$ crystal is heated in an atmosphere of $Na$ vapours, it becomes yellow.


Therefore, all statements are correct.

Multiple choice imperfections in solids solid state the solid state chemistry

Which of the following statements is/are correct ?

  1. If three $Fe^{2+ }$ ions are missing from their lattice in FeO, there must be two $Fe^{3+ }$ ions somewhere in the lattice.

  2. Crystals with metal deficiency defects are called super conductors.

  3. Crystals with metal deficiency are called semiconductors.
  4. Bohr Magneton = $9.27 \times 10^{-24} A \:m^2$.
Reveal answer Fill a bubble to check yourself
A,C,D Correct answer
Explanation

The statements A, C and D are correct.
(A) If three $Fe^{2+}$ ions are missing from their lattice in FeO,  there must be two $Fe^{3+}$ ions somewhere in the lattice.
The charge on three $Fe^{2+}$ ions is $3 \times (+2) = +6$
The charge on two $Fe^{3+}$ ions is $2 \times{3+} = +6$
Thus, the electrical neutrality is maintained.

Two type of vacancies of iron are present here. This is called crystal with metal deficiency defect.

(B) Crystals with metal deficiency defects are not called super conductors. The idea of Superconductors is that it possesses zero resistance at a certain temperature. 

(C) Crystals with metal deficiency are called semiconductors.

(D) Bohr Magneton = $9.27 \times 10^{-24} A :m^2$.
The orbital or spin magnetic momentum of an electron is expressed in terms of Bohr magneton. Its symbol is $\mu _B$.

Except option B all are correct.

Multiple choice imperfections in solids solid state the solid state chemistry
Assertion: Solids containing F centers are paramagnetic.
Reason: Solids containing F centers conduct electricity and it is an n-type semiconductor. 

  1. Both Assertion and Reason are correct and Reason is the correct explanation of Assertion

  2. Both Assertion and Reason are correct but Reason is not the correct explanation of Assertion

  3. Assertion is correct but Reason is not correct

  4. Assertion is not correct but Reason is correct

  5. Both Assertion and Reason are not correct
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

F centers are color centres consisting of an electron trapped by a negative ion vacancy in an ionic crystal such as an alkali halide or an alkaline-earth fluoride or oxide.
As F-center have free unpaired electron, they are paramagnetic in nature and because of this free electron, they conduct electricity.
Also, because of this extra electron, they form n-type semiconductor.

Multiple choice imperfections in solids solid state the solid state chemistry

A strong current of trivalent gaseous boron passed through a germanium crystal decreases the density of the crystal due to part replacement of germanium by boron and due to interstitial vacancies created by missing Ge atoms. In one such experiment, one gram of germanium is taken and the boron atoms are found to be $150$ ppm by weight when the density of the Ge crystal decreases by $4\%$. Calculate the percentage of missing vacancies due to germanium which are filled up by boron atoms. Atomic weight of Ge $= 72.6$ amu and $B = 11$ amu.

  1. $2.4\, \%$
  2. $1.2\, \%$
  3. $6.6\, \%$

  4. None of the above
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

As given,
$1$ g Germanium $\equiv  150$ ppm of Boron $=1.5 \times 10^{-4}$ g of Boron
$4\%$ decrease in density of Ge occurs in one experiment due to replacement of Ge by B.

The weight becomes $0.96$ g (Ge + B).
Hence, $0.04$ g is missing.
$0.04$ missing means $(0.04-0.00015)$ g Ge missing $= \dfrac{(0.04-0.00015)}{72.61}$ moles
Ge missing $=$ $5.488\times 10^{-4}$ moles
Boron replaced $=$ $1.5\times 10^{-4} g = \dfrac{(1.5\times 10^{-4})}{10}$ moles
Equivalently replaced $= \dfrac 34\times $ $\dfrac{1.5\times 10^{-4}}{10}$ moles of Ge ( Valency of B is $3$ and Ge is $4$.)
$=0.1125\times 10^{-4}$ moles of Ge
Percentage of missing vacancies filled by B atoms $=\dfrac {0.1125\times 100}{5.488}$ $=2.05\%$

Multiple choice imperfections in solids solid state the solid state chemistry

Crystals have 'vacant sites' or 'defects' in them. When light strikes a photographic silver bromide paper, silver atoms move in through these defects to:

  1. develop the film

  2. form tiny clumps of silver atoms

  3. form negative images

  4. form a colour image
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

When light strikes a photographer $(AgBr)$ paper, it gives energy to the electrons present in the film. These energetic electrons when strike silver ions turn them to silver atoms. So eventually,  ions leave their lattice site and occupy interstitial sites. Since silver atoms are black in color so whenever light strikes a silver ion the photographic film will turn black.

Multiple choice imperfections in solids solid state the solid state chemistry

The pink colour of lithium chloride crystal is due to:

  1. frenkel defect

  2. metal excess defect

  3. metal deficiency defect

  4. impurity defect
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

$LiCl$ has non-stochiometric metal excess defect due to anion vacancies. The negative ions $(Cl^-)$ are missing from their lattice sites leaving the holes in which electrons are entrapped so that electrical neutrality is maintained.

When $LiCl$ is heated, $Li$ atoms gets deposited on the surface of the crystal. The $Cl^-$ ions diffuse into the surface and combine with $Li$ atoms to give $LiCl$. This is so because of loss of electrons by $Li$ atoms to form $Li^+$. The released electrons diffuse excess into crystal and occupy anionic sites. As a result, there is an excess of $Li$. The anionic sites occupied by unpaired electrons are F-centers which imparts a pink color to $LiCl$ crystals. The color is observed as a result of excitation of these electrons when they absorb energy from visible light falling on crystals.

Multiple choice chemistry periodic table development of the modern periodic table into the history mendeleef's periodic table

The attempt for classifying elements by plotting the atomic masses of elements against the atomic volumes was made by:

  1. Dobereiner

  2. Newlands

  3. Lother Meyer

  4. Mendeleev
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

According to this if the atomic weights were plotted as ordinates and the atomic volumes as abscissae-the curve obtained a series of maxima and minima-the most electropositive elements appearing at the peaks of the curve in order of their atomic weights and electronegative element at the ascending positions.

Multiple choice chemistry periodic table development of the modern periodic table into the history mendeleef's periodic table

The attempt for classifying elements by plotting the atomic masses of elements against the volumes was made by:

  1. Dobereiner

  2. Newland

  3. Lother Meyer

  4. Mendeleev
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Lothar Meyer (1869) tried to classify by plotting a graph of atomic volume versus atomic masses of different elements. 


According to this if the atomic weights were plotted as ordinates and the atomic volumes as abscissae-the curve obtained a series of maxima and minima-the most electropositive elements appearing at the peaks of the curve in order of their atomic weights and electronegative element at the ascending positions.

Option C is correct.

Multiple choice chemistry periodic table development of the modern periodic table into the history mendeleef's periodic table

In Lother Meyer's curve most electronegative elements or halogens occupied ___________________.

  1. Peaks.

  2. Ascending positions.

  3. Descending positions.

  4. Halogens were not shown.
Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

According to this if the atomic weights were plotted as ordinates and the atomic volumes as abscissae-the curve obtained a series of maxima and minima-the most electropositive elements appearing at the peaks of the curve in order of their atomic weights and the electronegative element at the ascending positions.