Tag: chemistry

Questions Related to chemistry

Which compound does nitrogen have oxidation number in fraction?

  1. $NH _{2}OH$

  2. $N _{2}H _{4}$

  3. $NH _{3}$

  4. $N _{3}H$


Correct Option: D

How many of the following compound on thermal decomposition gives $N _2$ gas?
$(NH _4) _2 Cr _2 O _7$, $NH _4 NO _3$, $NH _4 IO _3$, $NH _4 NO _2$, $Ba(N _3) _2$, $Ba(NO _3) _2$, $(NH _4) _2 SO _4$, $(NH _4) _2 CO _3$

  1. 2

  2. 3

  3. 4

  4. 5


Correct Option: B
Explanation:

$(NH _4) _2Cr _2O _7\longrightarrow N _2+Cr _2O _3+H _2O$

$NH _4NO _3\longrightarrow N _2O+2H _2O$
$NH _4IO _3\longrightarrow$
$NH _4NO _2\longrightarrow N _2+2H _2O$
$Ba(N _3) _2\longrightarrow Ba+3N _2$
$Ba(NO _3) _2\longrightarrow BaO+NO _2+O _2$
$(NH _4) _2SO _4\longrightarrow NH _4HSO _4+NH _3$
$(NH _4) _2CO _3\longrightarrow 2NH _3+CO _2+H _2O$
$\therefore$ Answer is option B=3

All metals react with nitrogen on heating.
  1. True

  2. False


Correct Option: B

The mixed anhydride of nitrogen is:

  1. ${N} _{2}{O} _{2}(2NO)$

  2. ${N} _{2}{O} _{4}(2{NO} _{2})$

  3. ${N} _{2}{O} _{5}$

  4. ${N} _{2}{O} _{2}$


Correct Option: A
Explanation:
Mixed anhydride or double acid anhydride is the compound that reacts with water to form a mixture of two acidic anhydride.
Two oxides of nitrogen are acid anhydrides; that is, they react with water to form two nitrogen-containing oxyacids.

$2NO _2 + H _2O \longrightarrow HNO _3 + HNO _2$
 
Hence, the correct option is B.

The mixed anhydride of nitrogen is:

  1. $N _2O _2(2NO)$

  2. $N _2O _4(2NO _2)$

  3. $N _2O _5$

  4. $N _2O _3$


Correct Option: B
Explanation:

$NO _2$ is called as a mixed anhydride of nitrogen because it gives a mixture of $ HNO _2$ and $HNO _3$. Hence option (B) is correct .

An orange solid (X) on heating, gives a colourless gas (Y) and a only green residue (Z). Gas (Y) on treatment with Mg, produceds a white solid substance................

  1. $Mg _{3}N _{2}$

  2. $MgO$

  3. $Mg _{2}O _{3}$

  4. $MgCl _{2}$


Correct Option: A
Explanation:

$(NH _4) _2Cr _2O _7  \rightarrow N _2 + Cr _2O _3 + 4H _2O$
$3Mg + N _2 \rightarrow Mg _3N _2$
Orange solid is $(NH _4) _2Cr _2O _7$
Colourless gas is $N _2$
Green residue is $Cr _2O _3$

Metal (s) M in the following equation is/are 

${M+N\rightarrow  Metal  nitride}$ :

  1. Na

  2. Li

  3. Cs

  4. Mg


Correct Option: A,B,D
Explanation:

Except from Cs, all these metals form metal nitride $Na _3N, Li _3N, Mg _3N _2$.

At high temperatures,nitrogen directly combines with :

  1. Zn

  2. Mg

  3. Al

  4. Fe


Correct Option: B,C
Explanation:

At high temperatures, nitrogen directly combines with $Mg$ and$ Al$; forms nitride $AlN$ and $Mg _3N _2$.

Write the equation for the formation of ammonia by the action of water on magnesium nitride.

  1. $2{ Mg } _{ 3 }{ N } _{ 2 }+{ 6H } _{ 2 }O\rightarrow { 2NH } _{ 3 }+6Mg\left( OH \right) _{ 2 }$

  2. ${ Mg } _{ 3 }{ N } _{ 2 }+{ 3H } _{ 2 }O\rightarrow { NH } _{ 3 }+3Mg\left( OH \right) _{ 2 }$

  3. $3{ Mg } _{ 3 }{ N } _{ 2 }+{ 6H } _{ 2 }O\rightarrow { 6NH } _{ 3 }+3Mg\left( OH \right) _{ 2 }$

  4. ${ Mg } _{ 3 }{ N } _{ 2 }+{ 6H } _{ 2 }O\rightarrow { 2NH } _{ 3 }+3Mg\left( OH \right) _{ 2 }$


Correct Option: D
Explanation:

${ Mg } _{ 3 }{ N } _{ 2 }+{ 6H } _{ 2 }O\rightarrow { 2NH } _{ 3 }+3Mg\left( OH \right) _{ 2 }$

The following reactions are carried out: 

$A:$ Nitrogen + metal $\rightarrow$ compound $X$
$B:$ $X$ + water $\rightarrow$ ammonia + another compound 
$C:$ Ammonia + metal oxide $\rightarrow$ metal + water + $N _2$

One metal that can be used for reaction $A$ is magnesium. Write the correctly balanced equation for reaction $B$, where $X$ is the compound formed.

  1. ${Na }{ N } _{ 2 }+{ H } _{ 2 }O\rightarrow { NH } _{ 3 }+Na _2O$

  2. ${Mg } _{ 3 }{ N } _{ 2 }+{ 3H } _{ 2 }O\rightarrow { 2NH } _{ 3 }+ 3MgO$

  3. ${Ca } _{ 3 }{ N } _{ 2 }+{ H } _{ 2 }O\rightarrow { NH } _{ 3 }+CaO$

  4. None of these


Correct Option: D
Explanation:

One metal that can be used for reaction A is magnesium. So the corresponding reaction A is $N _2 + 3Mg\rightarrow Mg _3N _2$

Hence the compound X is $-\ Mg _3N _2$.
 

The complete reactions involving $Mg$ are as follows:

A: $N _2 + 3Mg\rightarrow Mg _3N _2$

B: $Mg _3N _2+6H _2O\rightarrow 3Mg(OH) _2+2NH _3$ 

C: $2NH _3+ 3MgO\rightarrow 3Mg+3H _2O+N _2$

The correct balanced equation for reaction B is $Mg _3N _2+6H _2O\rightarrow 3Mg(OH) _2+2NH _3$