Tag: chemistry

Questions Related to chemistry

$D _{2}O$ is:

  1. product of $O _{2}$ and $H _{2}$

  2. simple water in which present heavy metal salts

  3. marine water

  4. water which form redistillation and condensation


Correct Option: D
Explanation:
$D _{2}O$ is heavy water, which is a product of $O _{2}$ and $D _{2}$. Heavy water form redistillation and condensation.

Of the two solvent ${ H } _{ 2 }O$ and ${ D } _{ 2 }O$, $NaCl$ dissolves:

  1. equally in both solvents

  2. only in ${ H } _{ 2 }O$ but remains insoluble in ${ D } _{ 2 }O$

  3. more in ${ D } _{ 2 }O$

  4. more in ${ H } _{ 2 }O$


Correct Option: D
Explanation:

$NaCl$ (and other ionic compounds) dissolve more in $H _2O$ than in $D _2O$ as the dielectric constant of $H _2O$ $(78.39)$ is higher than the dielectric constant of $D _2O:(78.06)$. This is due to lower molar mass of $H _2O$ as compared to that of $D _2O$.

Which of the following is not the possible enol form of propanone in the presence of heavy water?

  1. ${ CH } _{ 3 }-CD=\overset { \overset { OD }{ | } }{ C } -D$

  2. ${ CH } _{ 3 }-\overset { \overset { OD }{ | } }{ C= } CHD$

  3. ${ CH } _{ 2 }=\overset { \overset { OD }{ | } }{ C- } { CD } _{ 3 }$

  4. ${ CD } _{ 2 }=\overset { \overset { OD }{ | } }{ C- } { CD } _{ 3 }$


Correct Option: A

Which one of the following statements is correct about $D _{2}O$ and $H _{2}O$?

  1. $D _{2}O$ has lower dielectric constant than $H _{2}O$

  2. $NaCl$ is more soluble in $D _{2}O$ than in $H _{2}O$

  3. Both (a) and (b) are correct

  4. None of the above


Correct Option: A

A water sample has ppm concentrations of the following metals

  1. Fe=0.2

  2. Mn=0.2

  3. Al=0.2

  4. Cu=0.2


Correct Option: B

Heavy water is used in atomic reactor as:

  1. coolant

  2. moderator

  3. both coolant and moderator

  4. neither coolant nor moderator


Correct Option: C
Explanation:

In atomic reactor, heavy water is used as coolant and moderator. As a coolant, it removes heat from the reactor and as a moderator, it slows down the speed of neutrons.

Which one of the following processes will produce hard water?

  1. Saturation of water with $CaCO _3$

  2. Addition of $Na _2SO _4$ to water.

  3. Saturation of water with $MgCO _3$

  4. Saturation of water with $CaSO _4$


Correct Option: A,C,D
Explanation:

Hard water is water that has high mineral content (in contrast with "soft water"). Hard water is formed when water percolates through deposits of calcium and magnesium-containing minerals such as limestone, chalk and dolomite.
The following processes will produce hard water
1. saturation of water with $CaCO _3$
2. saturation of water with $MgCO _3$
3. saturation of water with $CaSO _4$
Hence options A,B & D are correct.

$D _2O$ differ in the following except:

  1. freezing point

  2. density

  3. ionic product of water

  4. its reaction with sodium


Correct Option: D
Explanation:

The freezing point of water is $0 ^oC$, whereas the freezing point of heavy water is $3.8 ^0C$. 


At $20 ^0C$, the density of water is $0.9982$ g/mL, whereas the density of heavy water is $1.1056$ g/mL. 

Similarly, water and heavy water differ in the value of the ionic product. 

However, the chemical properties (such as reaction with sodium) of water are similar to that of heavy water due to the same electronic configuration.

$CH _3CH _2MgCl$ when reacts with heavy water, the product obtained is:

  1. $CD _3-CH _2 D$

  2. $CH _3 CH _2 - OD$

  3. $CD _3 - CD _3$

  4. $CH _3 CH _2 D$


Correct Option: D
Explanation:

The reaction of ethylmagnesium chloride with heavy water forms mono deuterated ethane. $CH _3CH _2MgCl + DOD \rightarrow CH _3CH _2D + MgClOD$.

During electrolysis bonds in $H _2O$ are broken 18 times faster than $D _2O$.

  1. True

  2. False


Correct Option: A
Explanation:

Due to the light weight of protium than deuterium, a bond to a protium atom can be broken $18$ times faster than the bond to a deuterium atom.