Tag: chemistry

Questions Related to chemistry

In the depression of freezing point experiment, it is found that
(i) The vapour pressure of the solution is less than that of pure solvent
(ii) The vapour pressure of the solution is more than that of pure solvent
(iii) Only solute molecules solidify at the freezing point
(iv) Only solvent molecules solidify at the freezing point

  1. I,II

  2. II,III

  3. I,IV

  4. I,II,III


Correct Option: C

Which one of the following would not be a suitable solvent for Grignard reagent?

  1. $CH _{3}CH _{2}OCH _{2}CH _{3}$, diethylether

  2. tetrahydrofuran (THF)

  3. $CH _{3}CH _{2}OH$, ethanol

  4. They would all be suitable solvent.


Correct Option: C
Explanation:

Ethanol has acidic hydrogen, when we use ethanol as solvent it will react with grignard reagent, so it cannot be used as solvent in grignard synthesis. 

Ullmann reaction involves the use of the following reactants:

  1. iodobenzene and sodium

  2. benzene and copper

  3. iodobenzene and copper powder

  4. benzene diazonium chloride and $Cu/HCl$


Correct Option: C
Explanation:

Statemetn (c) is Ullmann reaction
$2ArI+Cu\longrightarrow Ar-Ar+Cu{I} _{2}$

The interaction of elemental sulphur with Grignard reagent gives ......... .

  1. $H _2S$ gas

  2. Mercaptan

  3. thioalcohol

  4. $R-S-OH$


Correct Option: B,C
Explanation:

The interaction of elemental sulphur $(S)$ with grignard reagent $(RMgX)$ gives mercaptan $(RSH)$ which is also called thioalcohol.

Acetyl bromide reacts with excess of $CH _3MgI$ followed by treatment with a saturated solution of $NH _4Cl$ gives:

  1. acetone

  2. acetamide

  3. $2$-Methyl-$2$-propanone

  4. acetyl iodide


Correct Option: C
Explanation:

C. $2$-methyl-$2$-propanol
Acetyl chloride reacts with two equivalents of Grignard reagent to form tertiary alcohol, two of the groups bonded to $C$ having $O$H group are from the Grignard reagent.

The acid that cannot be prepared by Grignard reagent is.

  1. Acetic acid

  2. Formic acid

  3. Butyric acid

  4. Benzoic acid


Correct Option: B
Explanation:

Formic acid (containing only one C atom) cannot be prepared by Grignard reagent. The acid that can be prepared by Grignard reagent should contain a minimum of two carbon atoms. An example is as shown below.
$\displaystyle CO _2+CH _3-MgI \rightarrow CH _3-COO-MgI \xrightarrow [hydrolysis]{H^+} CH _3-COOH+ Mg(I)OH$

Grignard reagent is usually prepared by :

$R-X+Mg\xrightarrow {E{ t } _{ 2 }O} RMgX$               Grignard reagent

$Ar-X+Mg\xrightarrow {E{ t } _{ 2 }O} ArMgX$           Grignard reagent

Grignard reagent acts as a strong base. Grignard reagent carry out nucleophilic attack in absence of acidic hydrogen. Grignard reagent form complex with its ether solvent. Complex formation with molecule of ether is an important factor in the formation and stability of Grignard reagent.

Which of the following Grignard reagents are not possible ?

  1. $HS - CH _{2} - CH _{2} - CH _{2}MgBr$

  2. $HO - CH _{2} - CH _{2} - CH _{2}MgBr$

  3. $NH _{2} - CH _{2} - CH _{2} - CH _{2}MgBr$

  4. All of these


Correct Option: D
Explanation:

(A)$\overset {\delta +}{H}-S-CH _2CH _2CH _2-MgBr \xrightarrow [reaction]{acid-base} BrMgS-CH _2CH _2CH _3$


(B) $H-O-CH _2CH _2CH _2MgBr \xrightarrow [reaction]{acid-base} BrMgO-CH _2CH _2CH _3$


(C) $\overset {\delta +}{H}-\underset {|}{N}-CH _2CH _2-CH _2-MgBr \xrightarrow [reaction]{acid-base} BrMg-\underset {|}{N}-CH _2CH _2CH _3$
         $\delta^+ H$                                                                                        $H$

So, all of these Grignard reagent can take their own acidic hydrogen. Therefore all of these Grignard reagents are not possible.

A student was carrying out a Grignard reaction between $PhMgBr$ and ethyl benzoate. She ran out of anhydrous ether just after the Grignard reagent was made. Which of the following solvents can still used to dissolve the ethyl benzoate for its reaction with already formed $PhMgBr$

  1. acetone

  2. ethyl acetate

  3. absolute alcohol

  4. benzene


Correct Option: D
Explanation:

Solution:- (D) benzene

Grignard reagent contains $R$-group which does nucleophilic addition on acetone and accepts Proton from alcohol.
Thus non polar benzene should be taken to carry out above reaction. 

Which of the following Grignard reagent can be prepared? 

  1. $Br-Mg-{CH} _{2}-{CH} _{2}-{CH} _{2}O-H$

  2. $Br-Mg-{CH} _{2}-{CH} _{2}-SH$

  3. $BrMg-{CH} _{2}-{CH} _{2}-{NH} _{2}$

  4. $BrMg - CH _2- CH _2 - \underset{CH _3}{\underset{|}{N} -} CH _3$


Correct Option: D
Explanation:
Grignards reagent form via the reaction of an alkyl or aryl halide with magnesium metal.The reaction is conducted by adding the organic halide to a suspension of magnesium in an ethyal solugnt,which produce the reaction proceeds through a single electron transfer as:
$R-X+mg\longrightarrow R-X^-+Mg^+$
$R-X^-\longrightarrow R+X^-$
$R+Mg^+\longrightarrow RMg^+$
$RMg^++X^-\longrightarrow RMgX$
Thus,by the above way of preparing grignard reagent,compounds with carbonyl group $(C=O)$,$-SH$ group and $-NH _2$ group cannot be prepared .

In which of the following reactions, products are not correctly matched in:

  1. $RMgX +{CO _{2}}\xrightarrow[(ii)H^{\bigoplus }]{(i)CO _{2}}$Carboxylic acid

  2. $RMgX + C _{2}H _{5}OH \rightarrow$ Alkane

  3. $RMgX+CH _{3}CH _{2}Cl\rightarrow$ Alkene


Correct Option: C
Explanation:

Reaction:
$RMgX+CH _{3}CH _{2}Cl\rightarrow R-R$ alkane.