Tag: chemistry

Questions Related to chemistry

In the balanced equation for combustion of 1 mole of butane, $C _4H _{10}(g)$, the coefficient of oxygen is:

  1. 5/2

  2. 9/2

  3. 5

  4. 13/2


Correct Option: D
Explanation:
Balanced chemical reaction of butane:
$C _4H _{10}+\frac{13}{2}O _2\rightarrow4CO _2+5H _2O$

Standard enthalpy of formation $(\Delta H _f)$ of which of the following is zero at $25^0C$ ?

  1. White phosphorous

  2. Red phosphorous

  3. Red lead $(Pb _3O _4)$

  4. $H^+(g)$


Correct Option: A
Explanation:

White phosphors is the elemental form of phosphorus for which enthalpy of formation is zero, while, $H^+$ and $Pb _3O _4$ are not elemental forms.

The enthalpy of hydrogenation for $1-pentene$ is $+126\ kJ/mol$. The enthalpy of hydrogenation for $1, 3-pentadiene$ is $+230\ kJ/mol$. Hence estimate the resonance magnitude of (delocalization) energy of $1, 3-pentadiene$.

  1. $22\, kJ/mol$

  2. $104\, kJ/mol$

  3. $252\, kJ/mol$

  4. cannot be calculated from this information


Correct Option: A
Explanation:

Enthalpy of hydrogenation per bond$=+126\ kJ/mol$


Enthalpy of hydrogenation for 2 bonds$=+252\ kJ/mol$


Resonance energy$=252-230=22\ kJ/mol$

The least stable in amongst the following is:

  1. $Li^-$

  2. $Be$

  3. $B$

  4. $C$


Correct Option: A
Explanation:

$Li$ is alkali metal hence, the negative charge on $Li$ is least stable as it will have the lowest electronegativity.

The heats of neutralization of $CH _3COOH.HCOOH, HCN$ and $HClO$ are 13.2, 13.4,2.9 and 3.6 kcal/eq respectively. Then, the degree of hydrolysis for the respective ions will be in the order :

  1. $CH _3COO^- < HCOO^- < CN^- < ClO^-$

  2. $HCOO^- < ClO^- < CN^- < CH _3COO^-$

  3. $CH _3COO^- < CN^- < ClO^- < HCOO^-$

  4. $HCOO^- < CH _3COO^- < ClO^- < CN^-$


Correct Option: D
Explanation:

Strong acid have high heat of neutralization and are very much stable so required high energy for dissociation. Hence, weak acids are hydrolysed at faster rate than strong acids.

The heat change for the reaction: $C(s) + S(s)\rightarrow CS _2(l)$, known as:

  1. heat of transition

  2. heat of fusion

  3. heat of vapourisation

  4. heat of formation


Correct Option: D
Explanation:
$C(s)+2S(s)\rightarrow CS _2(l)$
The heat change of the reaction is enthalpy of formation as 1 mole of $CS _2$ is being formed from elemental state of carbon as well as Sulphur.

Enthalpy of a solution of $ CsBr(s)$ is $10\ kJ/mol$.If the enthalpies of hydration of $Cs^+(g)$ and $Br(g)$ are 475 and 655 kJ.mol, what should be the lattice energy of $CsBr(s)$ in $kJ/mol$:

  1. $1120$

  2. $1130$

  3. $1140$

  4. $1150$


Correct Option: C

Which statement about bonding is not correct?

  1. Carbon can form four single covalent bonds

  2. Chlorine atoms react to gain a noble gas electronic structure

  3. Covalent bonding involves losing and gaining electrons

  4. Hydrogen molecules have the formula $H _{2}$


Correct Option: C
Explanation:


Solution:- (C) Covalent bonding involves losing and gaining electrons

Covalent bonding involves sharing of electrons while the losing and gaining of electrons is found in ionic bonding.

Covalent bonds are formed when electrons are $1$ .
Most covalent compounds have $2$ electrical conductivity.
Which words correctly complete gaps $1$ and $2$?

  1. Shared - high

  2. Shared - low

  3. Transferred - high

  4. Transferred - low


Correct Option: B
Explanation:

Solution:- (B) Shared - low

  1. Covalent bonds are formed by sharing of electrons.
  2. Most covalent compounds have low electrical conductivity due to low mobility, i.e., no free electrons.

Compound $X$ consists of molecules.
In the liquid state X will

  1. becomes ionic

  2. be an electrolyte but not conduct electricity.

  3. conduct electricity only

  4. not conduct electricity

  5. non of the above


Correct Option: D
Explanation:

Compound X consists of molecules, so its covalent compounds and dont have any charged ions to conduct electricity so it will not conduct electricity.