Tag: chemistry

Questions Related to chemistry

HCl can be prepared by:

  1. $NaCl$ + $H _{2}SO _{4}$$\overset{420K}\rightarrow$

  2. $NaHSO _{4}$ + $NaCl$ $\overset{823K}\rightarrow$

  3. $NaNO _3$ + $H _{2}SO _{4}$ $\rightarrow$

  4. both (A) and (B).


Correct Option: D
Explanation:
HCl can be prepared by following :

$NaCl$ + $H _{2}SO _{4}$$\overset{420K}\rightarrow NaHSO _4+HCl$

$NaHSO _{4}$ + $NaCl$ $\overset{823K}\rightarrow Na _2SO _4+HCl$.

Hence option D is correct.

In which reaction equilibrium moves in left hand side when pressure is increased?

  1. $H _{2(g)} + Cl _{2(g)} \rightleftharpoons 2HCl _{(g)}$

  2. $2Mg _{(s)} + O _{2(g)} \rightleftharpoons 2MgO _{(s)}$

  3. $2H _{2}O _{(g)} \rightleftharpoons 2H _{2(g)} + O _{2(g)}$

  4. $N _{2(g)} + 3H _{2(g)} \rightleftharpoons 2NH _{3(g)}$


Correct Option: C
Formation of $HCl$ from its elements takes place in the presence of sunlight.
  1. True

  2. False


Correct Option: A
Explanation:

Hydrogen chloride is prepared from chlorine gas and hydrogen gas in the presence of UV light. This reaction is exothermic and the resulting HCl gas is absorbed in deionized water.

${ H } _{ 2 }+{ Cl } _{ 2 }\rightarrow 2HCl$

The compound which does not have oxygen is :

  1. nitric acid

  2. sodium hydroxide

  3. hydrochloric acid

  4. acetic acid


Correct Option: C
Explanation:

Nitric acid $(HNO _3)$ has 3 oxygen atoms in its formula.

Sodium hydroxide $(NaOH)$ has 1 oxygen atom in its formula.
Acetic acid $(CH _3COOH)$ has 2 oxygen atoms in its formula.
Hydrochloric acid $(HCl)$ does not have oxygen atom in its formula.

Hence, option C is correct.

Identify the gas evolved when potassium sulphite is treated with dilute hydrochloric acid.

  1. ${ S } _{ 2 }$

  2. ${ O } _{ 2 }$

  3. ${ SO } _{ 2 }$

  4. None of these


Correct Option: C
Explanation:

When potassium sulphite is treated with dilute hydrochloric acid, sulphur dioxide gas is evolved along with potassium chloride and water.


$ { K } _{ 2 }{ SO } _{ 3 }+HCl\rightarrow KCl + { H } _{ 2 }O+{ SO } _{ 2 }$

Hence, option C is correct.

Which of the following gas is evolved when concentrated hydrochloric acid is made to react with manganese dioxide?

  1. ${ O} _{ 3 }$

  2. ${ O } _{ 2 }$

  3. ${ H} _{ 2 }$

  4. ${ Cl } _{ 2 }$


Correct Option: D
Explanation:

When concentrated hydrochloric acid reacts with manganese dioxide, chlorine gas as well as manganese(II) chloride and water. 


${ MnO } _{ 2 }+4HCl\rightarrow { MnCl } _{ 2 }+{ Cl } _{ 2 }+2{ H } _{ 2 }O$

Hence, option $\text{D}$ is correct.

Iron reacts with hydrogen chloride gas-forming (iron [II] chloride, iron [III] chloride) and hydrogen, The reaction is an example of :

  1. double decomposition

  2. synthesis

  3. simple displacement

  4. None of these


Correct Option: C
Explanation:

Iron reacts with hydrogen chloride gas-forming iron$ [II] $ chloride and hydrogen. The reaction is an example of simple displacement reaction.


$Fe + 2HCl \longrightarrow FeCl _2 + H _2$


Hence, the correct answer is option $\text{D}$.

Hydrochloric acid can be converted into chlorine by heating with :

  1. calcium oxide

  2. lead [III] oxide

  3. lead [IV] oxide

  4. lead [II] oxide


Correct Option: C
Explanation:

Explanation :-

In $HCl$, the chlorine atom present with $-1$ oxidation state and $Cl _2$ has zero oxidation state. It means chlorine undergoes reduction that is only possible in the presence of a strong oxidizing agent.

$\underset{agent (Pb \ in \ +4 \ state)}{\underset{strong \ oxidizing}{PbO _2}} + 4HCl \rightarrow PbCl _2 + Cl _2 + 2H _2O$

Compounds $A$ and $B$ are treated with dilute $HCl$ separately. The gases liberated are $Y$ and $Z$ respectively $Y$ turns acidified dichromate paper green while $Z$ turns lead acetate paper black. So $A$ and $B$ compounds are respectively:

  1. $Na _2SO _3, Na _2S$

  2. $NaCl, Na _2CO _3$

  3. $Na _2S, Na _2SO _3$

  4. $Na _2SO _3, K _2SO _4$


Correct Option: A

On adding few drops of dil. HCl to freshly precipitated ferric hydroxide, a red coloured colloidal solution is obtained. The phenomenon is known as :

  1. protective action

  2. flocculation

  3. coagulation

  4. peptisation


Correct Option: D
Explanation:

Peptization is the process of forming stable colloids by using an electrolyte to break up a precipitate and disperse it into the colloid


Hence, option D is correct.