Tag: web technology

To answer this question, let's go through each line of code:

1. String s1 = "Amit"; - This line creates a string variable s1 and assigns it the value "Amit".
2. String s2 = "Amit"; - This line creates another string variable s2 and assigns it the value "Amit". Since string literals are interned in Java, both s1 and s2 refer to the same object in memory.
3. String s3 = new String("abcd"); - This line creates a new string object s3 using the new keyword. This will create a new object in memory with the value "abcd".
4. String s4 = new String("abcd"); - This line creates another new string object s4 using the new keyword. This will also create a new object in memory with the value "abcd".
5. System.out.println(s1.equals(s2)); - This line compares the values of s1 and s2 using the equals() method. Since both s1 and s2 have the same value ("Amit"), the equals() method will return true.
6. System.out.println((s1==s2)); - This line compares the references of s1 and s2 using the == operator. Since both s1 and s2 refer to the same object in memory, the == operator will return true.
7. System.out.println(s3.equals(s4)); - This line compares the values of s3 and s4 using the equals() method. Since both s3 and s4 have the same value ("abcd"), the equals() method will return true.
8. System.out.println((s3==s4)); - This line compares the references of s3 and s4 using the == operator. Since s3 and s4 are separate objects created using the new keyword, they refer to different objects in memory. Therefore, the == operator will return false.

Based on the above explanations, the correct answer is A) True true true false.

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• Wrong explanation