To solve this question, the user needs to understand the difference between the Math.floor(), Math.round(), Math.ceil(), and Math.min() methods in Java.
- Math.floor() returns the largest (closest to positive infinity) double value that is less than or equal to the argument and is equal to a mathematical integer.
- Math.round() returns the closest long or int, as given by the methods of the same name, to the argument, with ties rounding to positive infinity.
- Math.ceil() returns the smallest (closest to negative infinity) double value that is greater than or equal to the argument and is equal to a mathematical integer.
- Math.min() returns the smaller of two double values as an argument.
Now, let's go through each option and determine which one will output -4.0:
A. System.out.println(Math.floor(-4.7));
- This option will output -5.0 because Math.floor() returns the largest double value that is less than or equal to the argument, which in this case is -5.0.
B. System.out.println(Math.round(-4.7));
- This option will output -5 because Math.round() returns the closest long or int to the argument, which in this case is -5.
C. System.out.println(Math.ceil(-4.7));
- This option will output -4.0 because Math.ceil() returns the smallest double value that is greater than or equal to the argument, which in this case is -4.0.
D. System.out.println(Math.min(-4.7));
- This option will not compile because Math.min() requires two arguments, and only one is given.
Therefore, the answer is:
The Answer is: C