To determine the values of x and y after executing the given code, let's go through each line of the code step by step:
int x=20, y=35; - This line initializes the variables x and y with the values 20 and 35, respectively.x = y++ + x++; - This line assigns the value of y++ + x++ to x.
y++ is a post-increment operation, meaning that the value of y is used first and then incremented by 1. So, y++ evaluates to 35, and y becomes 36.- Similarly,
x++ is a post-increment operation, so x++ evaluates to 20, and x becomes 21.
- Therefore,
x is assigned the value 35 + 20 = 55.
y = ++y + ++x; - This line assigns the value of ++y + ++x to y.
++y is a pre-increment operation, meaning that the value of y is incremented by 1 first and then used. So, ++y evaluates to 37, and y becomes 37.- Similarly,
++x is a pre-increment operation, so ++x evaluates to 22, and x becomes 22.
- Therefore,
y is assigned the value 37 + 22 = 59.
printf(" %d %d", x, y); - This line prints the values of x and y.
Therefore, the output of the code will be 55 59.
The correct answer is not listed among the options provided.