Questions Related to physics

Multiple choice logarithm and its uses basic mathematical concepts physics

If $\displaystyle { log } _{ 5 }{ log } _{ 5 }{ log } _{ 2 }x=0$, then the value of $x$ is

  1. $32$

  2. $125$

  3. $625$

  4. $25$

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Given, $\displaystyle { log } _{ 5 }{ log } _{ 5 }{ log } _{ 2 }x=0$
$\displaystyle \Rightarrow \quad { log } _{ 5 }{ log } _{ 2 }x=50$
$\displaystyle \Rightarrow \quad { log } _{ 5 }{ log } _{ 2 }x=1\Rightarrow { log } _{ 2 }x=5$
$\displaystyle \Rightarrow x={ 2 }^{ 5 }=32$

Multiple choice logarithm and its uses basic mathematical concepts physics

The value of $\log _{10} 0.0006024$ is equal to

  1. $\overline {3}.7979$

  2. $\overline {1}.9779$

  3. $\overline {4}.7799$

  4. $0.7279$

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

$\log _{10}0.0006024$

Characteristics$=-4$
For mantissa ,read from the table $6024.$
Mantissa$=7799$ 
Thus, $\log _{10}0.0006024=$ characteristics of $0.0006024+$ mantissa of $0.0006024$
$=-4+0.7799$
$=\bar4.7799$
Hence, C is the correct option.

Multiple choice logarithm and its uses basic mathematical concepts physics

Using logarithm table, determine the value of $\log _{10}0.5432$.

  1. $\overline {1}.7350$

  2. <span>$\overline {2}.7350$</span>

  3. <span>$0.7350$</span>

  4. <span>$0.07350$</span>

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

$\log _{10}0.5432$

Characteristics$=-1$
For mantissa ,read from the table $5432.$
Mantissa$=7350$ 
Thus, $\log _{10}0.5432=$ characteristics of $0.5432+$ mantissa of $0.5432$
$=-1+0.7350$
$=\bar1.7350$
Hence, A is the correct option.

Multiple choice logarithm and its uses basic mathematical concepts physics

Antilog of the number $( -8.654)$ is equal to

  1. $2.18\times 10^{-8}$

  2. $2.18\times 10^{-9}$

  3. $2.218\times 10^{-9}$

  4. $2.218\times 10^{-8}$

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation
$(-8.654)=-8+(-0.654)$
$=-8+(-0.654)+1-1$
$=-9+(1-0.654)=-9+0.346$

Actual digits of 0.346 from the log table $=2.218$

$\therefore$ $ anti \log(-8.654)=2.218\times 10^{-9}$
Multiple choice logarithm and its uses basic mathematical concepts physics

The antilog of $\overline {1}.8840$is equal to

  1. $76.56$

  2. $\overline {1}.7656$

  3. $0.7656$

  4. $7.656$

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

Antilog $\bar1.8840$

Characteristics$=-1$
Value of $0.8840$ from antilog table $=7656$

Now number of zeroes after decimal will be $0.$
Antilog $\bar1.8840=0.7656$
Hence, C is the correct option.

Multiple choice logarithm and its uses basic mathematical concepts physics

The antilog of the number $2.9586$ is equal to

  1. $909.1$

  2. $90.91$

  3. $9.091$

  4. $0.9091$

Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

The number before decimal point is $2,$ so decimal point will be after $3$ digits.

Value of $0.9586$ from antilog table $=9078+12=9090$
Now place a decimal point after $3$ digits of the number from left we get, $909.0$
Antilog $2.9586=909.0$
Hence, A is the correct option.

Multiple choice logarithm and its uses basic mathematical concepts physics

The antilog of $(1.32)$ is equal to

  1. $20$

  2. $20.98$

  3. $20.89$

  4. $20.79$

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

The number before decimal point is $1,$ so decimal point will be after $2$ digits.

Value of $1.32$ from antilog table $=2089$
Now place a decimal point after $2$ digits of the number from left we get, $20.89$
Antilog $1.32=20.89$
Hence, C is the correct option.

Multiple choice logarithm and its uses basic mathematical concepts physics

The antilog of the number $0.2015$ is equal to

  1. $\overline {1}.1591$

  2. $1.591$

  3. $0.01591$

  4. $15.91$

Reveal answer Fill a bubble to check yourself
B Correct answer
Explanation

The number before decimal point is $0,$ so decimal point will be after $1$ digits.

Value of $0.2015$ from antilog table $=1589+2+=1591$
Now place a decimal point after $1$ digits of the number from left we get, $1.591$
Antilog $0.2015=1.591$
Hence, B is the correct option.

Multiple choice logarithm and its uses basic mathematical concepts physics

If there are $n$ zeros after the decimal point, then the characteristic of that number will be

  1. $n+1$

  2. $-n+1$

  3. $-(n+1)$

  4. $n-1$

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

For number less than $1,$ if there are $n$ zeroes after the decimal point, then the characteristics of that number will be $-(n+1).$

and For number  greater than $1,$ if  there are $n$ number of zeroes are on the left sides of the digits then characteristics will be $(n+1).$
Hence, C is the correct option.

Multiple choice logarithm and its uses basic mathematical concepts physics

Evaluate using log tables: $\sqrt [3] {\dfrac {16.23}{426.8}}$

  1. <span>$0.6332$</span>

  2. <span>$0.3632$</span>

  3. $0.3362$

  4. <span>$0.3624$</span>

Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

$\log { y } =\cfrac { 1 }{ 3 } \left[ \log { (16.23) } -\log { (426.8) }  \right] \ \log { y } =\cfrac { 1 }{ 3 } \left[ 1.2103-2.63022 \right] \ \log { y } =-0.4733\ y={ 10 }^{ -0.4733 }=0.3362$