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Multiple choice physics nuclear physics beta decay change in nucleus due to radioactive decay alpha, beta and gamma particles (rays) and their properties

The radius of spherical nucleus as measured by electron scattering is 36. fm. what is the likely mass number of the nucleus?

  1. 27

  2. 40

  3. 56

  4. 120
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation

Nuclear radius R = R0 * A^(1/3), where R0 is approx 1.2 fm. 36 = 1.2 * A^(1/3). A^(1/3) = 30. A = 30^3 = 27000. This calculation suggests the value 36 fm is very large. If R0 = 1.2, A = 27 is R = 1.2 * 3 = 3.6 fm. The question likely meant 3.6 fm.

Multiple choice physics nuclear physics beta decay change in nucleus due to radioactive decay alpha, beta and gamma particles (rays) and their properties

A bone containing 200 g carbon-14 has a $\beta $ decay rate of 375 deacy/min. Calculate the time that has elapsed since the death of the living one. Given the rate of decay for the living organism is equal to 15 decay per min per gram of carbon and half - life of carbon -14 is 5730 years,

  1. 27190 years

  2. 1190 years

  3. 17190 years

  4. None of these
Reveal answer Fill a bubble to check yourself
A Correct answer
Multiple choice physics nuclear physics beta decay change in nucleus due to radioactive decay alpha, beta and gamma particles (rays) and their properties

From the following the wrong statement is:

  1. Half-life of a free neutron is $10.3$ minutes

  2. The stability of a nucleus is only determined by the number of neutrons present in it.

  3. Both fast and slow neutrons are capable of penetrating the nucleus

  4. A free neutron decays into a proton, an electron and positron
Reveal answer Fill a bubble to check yourself
D Correct answer
Explanation

A free neutron will decay with a half life of about $10.3$ minutes but it is stable if combined into a nucleus. The stability of a nucleus is determined by number of neutrons as well as protons, Only fast moving neutrons are capable of penetrating the nucleus.A few neutron decays into a proton, an electron and anti-neutrino, and other options are known facts.

Multiple choice physics nuclear physics beta decay change in nucleus due to radioactive decay alpha, beta and gamma particles (rays) and their properties

When $ _{3}Li^{7}$ nuclei are bombarded by protons, and the resultant nuclei are $ _{4}Be^{8}$ , the emitted particles will be.   

  1. alpha particles

  2. beta particles

  3. gamma photons

  4. neutrons
Reveal answer Fill a bubble to check yourself
C Correct answer
Explanation

$ _{3}Li^{7} + ^{1} _{1}P \Rightarrow  _{4}Be^{8} + _{0}^{0}\gamma (energy)$
As, the emitted particles is only energy and gamma photons radiation is nothing but energy so, option  C is correct.

Multiple choice physics nuclear physics beta decay change in nucleus due to radioactive decay alpha, beta and gamma particles (rays) and their properties

Which of the following assertions are correct?

  1. A neutron can decay to a proton only inside a nucleus

  2. A proton can change to a neutron only inside nucleus

  3. An isolated neutron can change into a proton

  4. An isolated proton can change int a neutron
Reveal answer Fill a bubble to check yourself
B,C Correct answer
Explanation

$\beta^{+}$ decay cannot occur in an isolated proton because it requires energy due to the mass of the neutron being greater than the mass of the proton. $\beta^{+}$ decay can only happen inside nuclei when the daughter nucleus has a greater binding energy.


an isolated neutron is not stable outside hence it decays emitting a proton.

Multiple choice physics nuclear physics beta decay change in nucleus due to radioactive decay alpha, beta and gamma particles (rays) and their properties

If $ _{5}\textrm{B}^{11}$ converts into $ _{6}\textrm{C}^{11}$, then the particle emitted in this process will be 

  1. electron

  2. proton

  3. neutron

  4. positron
Reveal answer Fill a bubble to check yourself
A Correct answer
Explanation
$\beta ^-$ minus decay produces an electron and electron anti neutrino.
$\beta ^-$ decay increases the proton by $1$ and reduces the neutron number by $1$
Hence, mass number remains same but atomic number increase by $1.$