Tag: physics

Questions Related to physics

Phase difference between a particle at a compression and a particle at the next rarefaction is

  1. Zero

  2. $\dfrac{\pi}{2}$

  3. $\pi$

  4. $\dfrac{\pi}{4}$


Correct Option: C
Explanation:

Phase difference between two successive compression of rarefaction is $2\pi $
As  rarefaction appears between two compression, phase difference is $\pi $.

Which of the following is wrong about infrared rays?

  1. Infrared rays have wavelength higher than that of microwaves

  2. Infrared rays have wavelength lower than that of visible light

  3. Wavelength of these rays is of the order of $10^{-4}$ m

  4. The sources of infrared rays are always natural


Correct Option: C

The phase difference between two waves represented by 
${y _1} = {10^{ - 6}}\sin \left[ {100t + \frac{x}{{50}} + 0.5} \right]m$
${y _2} = {10^{ - 6}}\cos \left[ {100t + \frac{x}{{50}}} \right]m$
where x is expressed in metres and t is expressed in seconds is approximately

  1. 1.07 rad

  2. 2.07 rad

  3. 0.5 rad

  4. 1.5 rad


Correct Option: A
Explanation:
$y _{1}=10^{-6} \sin \left[100 t + \dfrac{x}{50}+ 0.5\right] m$
$y _{2}=10^{-6} \cos \left[100 t + \dfrac{x}{50}\right] m$
So,$y^{1}=10^{-6} \cos\left[\dfrac{\pi}{2}-\left(100 t + \dfrac{x}{50}+0.5\right)\right]$
$y^{1}=10^{-6} \cos \left[\dfrac{-\pi}{2}+100 t+\dfrac{x}{50}+0.5\right]$
$\triangle \phi =\phi _{2}-\phi _{1}$
$\phi _{2}=0$ where as $\phi _{1}=0.5-\dfrac{\pi}{2}$
So,
$\triangle \phi=\phi _{2}-\phi _{1}=\dfrac{\pi}{2}-0.5=1.07 \ rad$
option $-A$ is correct.

































Two waves of the same amplitude and frequency arrive at a point simultaneously. what should the phase difference between the waves so that amplitude of the resultant wave is double(2A) 

  1. $\dfrac {\pi}{2} radian$

  2. $\dfrac {2\pi}{3} radian$

  3. $\dfrac {3\pi}{4} radian$

  4. zero


Correct Option: D

Phase difference between a compression and its successful rarefaction is $2 \pi $radians

  1. True

  2. False


Correct Option: B
Explanation:

Phase difference between a crest and its successive trough is $ \pi $radians

A travelling wave has a velocity of 400 m/s and has a wavelength of 0.5 m. What is the phase difference between two points in the wave that are 1.25 milli secs apart

  1. $2 \pi$

  2. $2 \pi/3$

  3. $2 \pi/5$

  4. $ \pi/6$


Correct Option: A
Explanation:

The frequency of the wave is $f = v/\lambda=400/0.5=800 Hz$

Time period = 1/800 = 1.25 ms

Thus, both the points are one time period apart. Hence their phase difference will be zero or $2 \pi$

The correct option is (a)

Two waves of frequencies 20 Hz and 30 Hz travels out from a common point. The phase difference between them after 0.6 sec is

  1. $12\pi $

  2. ${\pi \over 2}$

  3. $\pi $

  4. ${{3\pi } \over 4}$


Correct Option: A
Explanation:

Beats period$=\cfrac{1}{30-20}=0.1second\ \Delta Y=\cfrac{2\pi}{T}\Delta t\ \quad=\cfrac{2\pi}{0.1}\times0.6=2\pi\times6=12\pi\ \therefore\Delta Y=12\pi$

A progressive wave of wavelength 5 cm moves along +X axis. What is the phase difference between two points on the wave separated by a distance of 3 cm at any instant

  1. $3 \pi/5$

  2. $6 \pi/5$

  3. $2 \pi/5$

  4. $7 \pi/5$


Correct Option: B
Explanation:

Phase difference = $(2\pi/5)$ path difference $\implies$ phase difference = $6 \pi/5$

The correct option is (b) 

The phase difference between two waves, represented by ${ y } _{ 1 }={ 10 }^{ -6 }\sin { \left[ 100t+\left( x/50 \right) +0.5 \right]\ m } $ and ${ y } _{ 2 }={ 10 }^{ -6 }\cos { \left[ 100t+\left( x/50 \right)  \right]\ m } $. Where $x$ is expressed in metre and $t$ is expressed in seconds, is approximately

  1. $1.07\ radian$

  2. $2.07\ radian$

  3. $0.5\ radian$

  4. $1.5\ radian$


Correct Option: A

The irreducible phase difference in any wave of 5000 A from a source of light is

  1. $\pi$

  2. $12\pi$

  3. $12\pi \times{10}^{6}$

  4. $\pi \times {10}^{6}$


Correct Option: A