Tag: physics

Questions Related to physics

A short linear object of length $b$ lies along the axis of a concave mirror of focal length $f$ at a distance u from the pole of the mirror. The size of the image is approximately equal to :

  1. $b\left (\dfrac {u-f}{f}\right )^{\dfrac {1}{2}}$

  2. $b\left (\dfrac {b}{u-f}\right )^{\dfrac {1}{2}}$

  3. $b\left (\dfrac {u-f}{f}\right )$

  4. $b\left (\dfrac {f}{u-f}\right )^2$


Correct Option: D
Explanation:

From mirror formula,


$\cfrac { 1 }{ v } +\cfrac { 1 }{ u } =\cfrac { 1 }{ f } \longrightarrow (1)$

Differentiating, we get  


$\Rightarrow -{ \upsilon  }^{ -2 }dv-{ u }^{ -2 }du=0$

or $\left| d\upsilon  \right| =\left| \cfrac { { \upsilon  }^{ 2 } }{ { u }^{ 2 } }  \right| du \ \longrightarrow (2)$         

Here $\left| dv \right| =$size of image,

$\left| du \right| =$size of object $\left( =b \right) $

From the equation $1$, we write

$\cfrac { u }{ v } +1 =\cfrac { u }{ f } $

Squaring both sides, we get

$\cfrac { { \upsilon  }^{ 2 } }{ { v }^{ 2 } } ={ \left( \cfrac { f }{ u-f }  \right)  }^{ 2 }$

Substituting in equation $2$ we get

Size of the image  $dv=b{ \left( \cfrac { f }{ u-f }  \right)  }^{ 2 }$

Magnification for erect and invented image is

  1. $+ve$ and $-ve$ respectively

  2. $-ve$ and $+ve$ respectively

  3. $+ve$

  4. $-ve$


Correct Option: A
Explanation:

Magnification is the ratio of height of image and object .

And by convention , height of image formed below principal axis is taken negative and above is taken positive.

Hence, for erect image, $m=+ve$ and for inverted image $m=-ve$.

Answer-(A).

The SI unit of specific latent heat is 

  1. $Jkg^{-1}K^{-1}$

  2. $J^{0}K^{-1}$

  3. $J kg^{-1}$

  4. $J kgK^{-1}$


Correct Option: C
Explanation:

The specific latent heat of a substance is the quantity of heat energy required to change the state of a unit mass of a substance.

${E} _{L}= ml$

here ${E} _{L}$ is the heat transferred, in joules,m is the mass, in kilograms, and l is the latent heat in joules per kilogram.

The SI unit for specific latent heat is $J{kg}^{-1}$.

The specific heat capacity of water in SI unit is :

  1. $4.2 Jg^{-1}K^{-1}$

  2. $42 Jg^{-1}K^{-1}$

  3. $420 J kg^{-1}K^{-1}$

  4. $4200 J kg^{-1}K^{-1}$


Correct Option: D
Explanation:

The specific heat capacity  of a substance is the heat needed to raise

the temperature of 1 kg of the substance by 1K (or by ${1}^{0}C$).
The specific heat capacity of water is $4200 J{kg}^{-1}{K}^{-1}$.

The SI unit of thermal capacity is ;

  1. $J\ kg^{-1}\  K^{-1}$

  2. $J^{-1}\ kg\ K^{-1}$

  3. $JK^{-1}$

  4. $J\  kg\ K^{-1}$


Correct Option: C
Explanation:


The heat or thermal capacity of a defined system is the amount of heat required to raise the system's temperature by one degree. It is expressed in units of thermal energy per degree temperature.

$q= C\times t$

$C=\dfrac{q}{\triangle t}$

here,$C=$heat or thermal capacity
        $q=$heat required (J)
        $\triangle t={t} _{1}-{t} _{2}$ (K)

so,The S.I. unit of heat or thermal capacity is $J{K}^{-1}$

Potential is measured in

  1. joule/coulomb

  2. watt/coulomb

  3. newton-second

  4. none of these


Correct Option: A
Explanation:

Potential is work done per unit charge $\displaystyle =\frac {J}{c}$

Name the physical quantity related to the following unit : watt.

  1. $Force$

  2. $Power$

  3. $Work$

  4. $Pressure$


Correct Option: B
Explanation:

Watt is  the SI unit of power, equivalent to one joule per second.

Power $=$ force $\times$ velocity $=$ Work/time
So, $watt=Nms^{-1}=J/s$

Name the physical quantity related to the following unit : pascal.

  1. $Force$

  2. $Pressure$

  3. $Work$

  4. $Distance$


Correct Option: B
Explanation:

The pascal (symbol: Pa) is the SI derived unit of pressure, internal pressure, stress, Young's modulus.

Pressure $=\dfrac{Force}{Area}$ 
So, $1\ pascal=1\ N/m^2$

Column I gives three physical quantities. Select the appropriate units for these from the choices given in column II. Some of the physical quantities may have more than one choice.

Column-I Column - II
a) Capacitance d) Ohm second
b) Inductance e) Coulomb$^{2}$ joule$^{ -1 }$
c) Magnetic induction f) Coulomb volt$^{ -1 }$
g) Newton (ampere/metre)$^{ -1 }$
h) Volt second (ampere)$^{ -1 }$
  1. a-e,f; b-d,h; c-g

  2. a-h; b-d; c-e

  3. a-e; b-g,h; c-g

  4. a-e,f; b-d,h; c-d,e


Correct Option: A
Explanation:

Capacitance is charge per unit volt. 

Volt has unit of work per unit chage. 
So capacitance has units of charge square per unit energy. 
Inductance is defined as volt per unit rate of change of current and voltage per unit current is resistance, so inductance is ohm second. 

The SI unit of magnetic permeability is

  1. ${ Am }^{ -1 }$

  2. ${ Am }^{ -2 }$

  3. ${ Hm }^{ -2 }$

  4. ${ Hm }^{ -1 }$


Correct Option: D
Explanation:

The correct option is D.

The magnetic permeability of any material is its property for allowing the magnetic line of force to pass through it. Therefore, the magnetic material can support the development of the magnetic field. This capability is measured by the magnetic permeability. Also, the magnetic line of force is directly proportional to the conductivity of the material. Its SI unit is Henry per meter i.e. $Hm^{-1}$ or newton per ampere square.